Question

人，

我有两张桌子：

表1：

UID    NAME
1      Name1
2      Name2
3      Name3

表2：

UID    PID    PARAM
1      1     10
2      1     20
3      2     10
4      2     30
5      2     40
6      3     60
7      3     20
8      3     10

我需要加入两个表（t1.UID = t2.PID）并仅列出第一个表中的记录，这些记录在第二个表中有（例如）BOTH PARAM = 10 AND PARAM = 20。这样，对于此示例，查询应返回：

UID      NAME
1        Name1
3        Name3

..因为只有Name1和Name3具有BOTH PARAM = 10 AND PARAM = 20

我该怎么做？我知道这可能很简单，但我也找不到答案，也不在谷歌。

提前谢谢！奈德

Answer 1

select a.name          
from table1 a
inner join table2 b on (a.UID = b.PID)
where b.param in (10, 20)
group by a.name
having count(*) = 2

通过声明您的表table1 a，您可以通过将表声明名称放在列a.name

中来调用此表中的任何列

Answer 2

此查询应该有效：

SELECT t1.* 
FROM table1 t1 
     INNER JOIN (SELECT PID 
                 FROM table2  
                 WHERE PARAM IN(10, 20)
                 GROUP BY PID
                 HAVING COUNT(*) = 2
                )t2
                ON t1.UID = t2.PID;

Answer 3

select distinct t1.id 
from table1 t1 join table2 t2 on t1.uid = t2.pid and t2.param = 10 
               join table2 t3 on t1.uid = t3.pid and t3.param = 20

Answer 4

您无需加入：

SELECT * FROM TABLE1 在哪里（从TABLE2中选择UID 参与的地方（10,20））

Answer 5

试试这个：

select uid,name from t1 where exists (select 1 from t2 where param = 10 and pid = t1.uid) and exists (select 1 from t2 where param = 20 and pid = t1.uid);

MySQL - 连接两个表，在第二个表中搜索

5 个答案: