通过查询我得到这个字符串"Order::Resource(PPP32#BB300320LQ00J#AAAR05504)"
。
我想在#字符之前,之间和之后提取字符串,如下所示:
id = PPP32
sub_id = BB300320LQ00J
sup_id = AAAR05504
有谁知道怎么做?
答案 0 :(得分:3)
declare @start int, @end int, @secondstring varchar(100)
select @start = charindex('#',@string)
select @secondstring = substring(@string, @start+1, len(@string))
select @end = charindex('#',@secondstring)
select substring(@string,1, @start-1),
substring(@string,@start+1,@end-1),
substring(@string, @start+@end+1, len(@string)-@end)
答案 1 :(得分:3)
这是正确的解决方案:
declare @string varchar(50)
select @string = 'Order::Resource(PPP32#BB300320LQ00J#AAAR05504)'
declare @start int, @end int, @secondstring varchar(100)
select @start = charindex('#',@string)
select @secondstring = substring(@string, @start+1, len(@string))
select @end = charindex('#',@secondstring)
select substring(@string,charindex('(', @string)+1, @start-1-charindex('(', @string)),
substring(@string,@start+1,@end-1),
substring(@string, @start+@end+1, len(@string)-(@start+@end+1))