Question

希望你能提供帮助，这正在推动我上去

我需要计算一个问题失败的次数百分比，但这需要根据地理区域进行缩小，并且产品会针对这些问题提出质疑。

我有：

$CA002 = "( SELECT ROUND(100 *  (SELECT count(CA002Result) from Data_Table where (CA002Result='Fail'))/count(CA002Result),2) from Data_Table) AS 'CA002 %'";

哪个“有效”，但只是将整个记录集计算为“整体”

我正在尝试：

$CA001 = "( SELECT ROUND(100 *  (SELECT count(CA001Result) from Data_Table where (CA001Result='Fail' AND Area ='$Area'))/count(CA001Result) from Data_Table WHERE (Area='$Area'),2) AS 'CA001 %'";

另外：

$CA001 = "( SELECT ROUND(100 * (SELECT count(CA001Result ) from Data_Table where (CA001Result='Fail' AND Product='$product' AND Area='$Area'))      
    /     count(CA001Result WHERE Product = '$product' AND Area='$Area'),2) from Data_Table) AS 'CA001 %'";

同样尝试这一点，但得到MYSQL语法错误。

$CA001 = "( SELECT ROUND(100 *  (SELECT count(CA001Result) from Data_Table where (CA001Result='Fail'))/ (SELECT (count(CA001Result) from Data_Table WHERE (Area='$Area')),2) AS 'CA001 %')";

无论我尝试什么，我只是得到错误，我似乎无法解决我需要放在哪里。

尝试以下答案：

$CA001 = "(SELECT 100 * SUM(IF(CA001Result='Fail', 1, 0)) / COUNT(CA001Result) as 'CA001 %' WHERE  Area='$Area')";

$CA002 = "( SELECT ROUND(100 *  (SELECT count(CA002Result) from Data_Table where (CA002Result='Fail'))/count(CA002Result),2) from Data_Table) AS 'CA002 %'";

但是我将以下内容视为错误：

MySQL错误：您的SQL语法出错;查看与您的MySQL服务器版本对应的手册，以便在'附近使用正确的语法'（SELECT ROUND（100 *（来自Data_Table的SELECT count（CA002Result））（CA002Re'在第1行

任何帮助，非常感谢，谢谢。

编辑 - 使用以下方法破解：

$CA001 ="ROUND ((SELECT 100 * SUM(IF(CA001Result='Fail', 1, 0)) / COUNT(CA001Result) 
FROM Data_Table
WHERE  Area='$Area'),2) as 'CA001 %'";

非常感谢你的帮助！

Answer 1

试试这个

SELECT 100 * SUM(IF(CA001Result='Fail', 1, 0)) / COUNT(CA001Result) as 'CA002 %'
FROM Data_Table
WHERE '$product' AND Area='$Area'

Answer 2

我只是猜测你的模型，但你应该尝试这种模式：

SELECT
    Area,
    Product,
    COUNT(*) as total,
    SUM(CA002Result='Fail') as total_fail,
    SUM(CA002Result='Fail') / COUNT(*) as 'CA002 %'
FROM Data_Table
GROUP BY Area, Product;

根据条件计算MYSQL查询中的百分比

2 个答案: