Question

我是PHP的新手，我需要一些帮助来爆炸文件中的数据。相关文件是：http://data.vattastic.com/vatsim-data.txt

基本上，我需要在!CLIENTS:部分（靠近底部）下获取数据。有了这些数据，我需要将其分解并获取每个:之间的信息。

我尝试过这段代码，但它给了我一个可变偏移量误差（Undefined offset: 3）

$file = file("http://data.vattastic.com/vatsim-data.txt");
foreach($file as $line)
{
   $data_record = explode(":", $line);

   // grab only the data that has "ATC" in it...
   if($data_record[3] == 'ATC' && $data_record[16] != '1' && $data_record[18] != '0'&&   stristr($data_record[0],'OBS') === FALSE)
   {
        rest of code here...
   }
}

如果有人可以帮助我，我会非常感激。

Answer 1

这是因为你试图像这样爆炸行：

！GENERAL包含常规设置

当你爆炸那条线时，你的$data_records看起来像这样：

阵列（ [0] =＆gt; ; ！GENERAL包含常规设置）

快速解决方案：

$file = file("http://data.vattastic.com/vatsim-data.txt");
foreach($file as $line)
{
   if(strpos($line,';') === 0) continue ; // this is comment. ignoring
   $data_record = explode(":", $line);
   $col_count = count($data_record);

   switch($col_count) {
     case 42: // columns qty = 42, so this is row from `clients`
      // grab only the data that has "ATC" in it...
      if($data_record[3] == 'ATC' && $data_record[16] != '1' && $data_record[18] != '0'&&   stristr($data_record[0],'OBS') === FALSE)
      {
           rest of code here...
      }
      break;
     default:
       // this is other kind of data, ignoring
       break;
   }
}

Answer 2

另一种解决方案是使用正则表达式并查找!CLIENTS:部分。这也适用于CLIENTS将来有多于或少于42列

的情况

$file = file_get_contents ("http://data.vattastic.com/vatsim-data.txt");  
$matches = null;
preg_match ('/!CLIENTS:\s\n(.*)\n;/s' , $file, $matches );
if($matches)
{
  $client_lines = explode("\n", $matches[1]);
  foreach ($client_lines as $client)
  {
    $data_record = explode(":", $client);
    if($data_record[3] == 'ATC' && $data_record[16] != '1' && $data_record[18] != '0'&&   stristr($data_record[0],'OBS') === FALSE)
    {
      //rest of code here...
    }
  }
}

抓取并爆炸数据

2 个答案: