我正在建立库存系统，我有一个页面，可以按类别查看销售历史记录，它将显示所有已售商品，销售数量，库存总量，剩余数量，销售额，利润等。 ..无论何时我按类别搜索（例如文具），显示如下所示。
Item Name stock qty sold qty total stock total amount profit
Books 990 45 75 60 1035 900 990 14567 15666 12666 1777 1555 17777
Sciences 825 45 75 60 1035 900 990 14567 15666 12666 1777 1555 17777
Comics 930 45 75 60 1035 900 990 14567 15666 12666 1777 1555 17777
但我真的想要的是：
Item Name stock qty sold qty total stock total amount profit
Books 990 45 1035 14567 1777
Sciences 825 75 1035 15666 1555
Comics 930 60 990 12666 17777
项目名称和库存数量已从数据库中调用并附加到列表中。对于销售的商品数量，我从数据库中调用此类商品的每个实例并计算其总数，然后附加到列表中。所以我想把他们各自的项目显示出来，同样适用于金额和专业。我只想要的是如何操纵模板以便适当地显示它。我的观点代码如下：
def search_category (request):
collate=[]
gains=[]
amount=[]
name=[]
store=[]
qty=[]
if 'q' in request.GET and request.GET['q']:
q = request.GET.get('q','')
items = Item.objects.filter(category__name__exact=q)
for item in items:
collate.append(item.subcategory.subcategoryname)
qty.append(int(item.quantity))
len_collate=len(collate)
count=0
#for pick in collate:
keep1=[]
amt_save=[]
gain_save=[]
t=[]
all_amt_save=[]
#sum=0
#t_amount=0
#t_gain=0
while count < len_collate:
soldqty=[]
#histories = RecordSales.objects.filter(ItemName__subcategoryname__exact=pick)#here
histories = RecordSales.objects.filter(ItemName__subcategoryname__exact=collate[count])
lenght=len(histories)
for history in histories:
soldqty.append(history.quantity)
#keep1=[] #array to store sum
len_qty=len(soldqty)
#count=0
#while count < lenght:
sum=0
sums=[]
t_stock=[]
#for num in soldqty:
count_qty=0
#for num in soldqty:
while count_qty < len_qty:
sum=sum + soldqty[count_qty]
#t_stock=qty[count_qty] + sum
count_qty=count_qty + 1
amount.append(history.total)
t_amount=0
amt_count=0
while amt_count < len(amount):
t_amount=t_amount + amount[amt_count]
amt_count=amt_count + 1
gains.append(history.profit)
t_gain=0
gain_count=0
while gain_count < len(gains):
t_gain=t_gain + gains[gain_count]
gain_count=gain_count + 1
name.append(history.ItemName)
#keep1.append(sum)
len_keep1=len(keep1)
amt_save.append(t_amount)
gain_save.append(t_gain)
count=count + 1
keep1.append(sum)
all_amt_count=0
all_amt_total=0
while all_amt_count < len(amt_save):
all_amt_total= all_amt_total + amt_save[all_amt_count]
#all_amt_save.append(all_amt_total)
all_amt_count=all_amt_count + 1
all_g_count=0
all_g_total=0
while all_g_count < len(gain_save):
all_g_total=all_g_total + gain_save[all_g_count]
all_g_count=all_g_count + 1
t_count=0
while t_count < len(keep1):
t_stock=keep1[t_count] + qty[t_count]
t_count=t_count + 1
store.append(t_stock)
total_amount=0
keep_total=[]
for total in amount:
total_amount=total_amount + total
keep_total.append(total_amount)
#total_amount=0
return render_to_response('sell_category.html',
{'items':items,'query': q,'keep1':keep1,'name':name,'items':items,
'keep_total':keep_total,'t':store,'amt_save':amt_save,'gain_save':gain_save,'all_amt':all_amt_total,'t_gain':all_g_total,'len':len_keep1,
})
else:
return render_to_response('sell_category.html', {'error': True})
感谢。
答案 0 :(得分：1)
当您将所有内容附加到列表中时，您可以使用zip()和一些字符串格式来获得所需的结果：
items=['Books','Sciences','Comics']
stock_qua=[990,825,930]
sold_qua=[45,75,60]
total_sto=[1035,1035,990]
total_amt=[14576,15666,12666]
profit=[1777,1555,1777]
print "{0:12s}{1:12s}{2:12s}{3:15s}{4:15s}{5:12s}".format("Item Name", "stock qty","sold qty","total stock","total amount","profit")
for item,stock,sold,tot_st,amt,pro in zip(items,stock_qua,sold_qua,total_sto,total_amt,profit):
print "{0:12s}{1:^10d}{2:^10d}{3:^15d}{4:^15d}{5:^12d}".format(item,stock,sold,tot_st,amt,pro)
<强>输出：
Item Name stock qty sold qty total stock total amount profit
Books 990 45 1035 14576 1777
Sciences 825 75 1035 15666 1555
Comics 930 60 990 12666 1777