从一个陷阱groovy返回

Question

我很困惑为什么这个方法总是会在捕获到异常时返回...在记录错误后它不应该返回吗？

private def sendConfCode(sendTo)
    {

        def confCode = genConfCode()
        try
        {
            mail.sendMessage(sendTo.toString(), "Your confirmation code is", confCode)
            //insert confCode into temporary banner table?
        }
        catch(Exception e)
        {
            logIt.writeLog(e.message, Priority.ERR)
        }
        return confCode + " - " + sendTo
    }

Answer 1

是的，它应该在记录错误后返回，如果确实抛出异常，这可能是记录器配置中的错误。

如果你想在catch块中停止执行，那么从那里返回

private def sendConfCode(sendTo)
    {

        def confCode = genConfCode()
        try
        {
            mail.sendMessage(sendTo.toString(), "Your confirmation code is", confCode)
            //insert confCode into temporary banner table?
        }
        catch(Exception e)
        {
            logIt.writeLog(e.message, Priority.ERR)
            return
        }
        return confCode + " - " + sendTo
}

Answer 2

正确的代码：

private def sendConfCode(sendTo)
    {

        def confCode = genConfCode()
        def sent=false
        try
        {

            mail.sendMessage(sendTo.toString(), "Your confirmation code is", confCode)
            //insert confCode into temporary banner table?
            sent = true
        }
    catch(Exception e)
    {
        logIt.writeLog(e.message, Priority.ERR)
    }
    return sent

}