Question

希望你能提供帮助，这正在推动我上去

我需要计算一个问题失败的次数百分比，但这需要根据地理区域进行缩小，并且产品会针对这些问题提出质疑。

我有：

$CA002 = "( SELECT ROUND(100 *  (SELECT count(CA002Result) from Data_Table where (CA002Result='Fail'))/count(CA002Result),2) from Data_Table) AS 'CA002 %'";

哪个“有效”，但只是将整个记录集计算为“整体”

我正在尝试：

$CA001 = "( SELECT ROUND(100 *  (SELECT count(CA001Result) from Data_Table where (CA001Result='Fail' AND Area ='$Area'))/count(CA001Result) from Data_Table WHERE (Area='$Area'),2) AS 'CA001 %'";

另外：

$CA001 = "( SELECT ROUND(100 * (SELECT count(CA001Result ) from Data_Table where (CA001Result='Fail' AND Product='$product' AND Area='$Area'))      
    /     count(CA001Result WHERE Product = '$product' AND Area='$Area'),2) from Data_Table) AS 'CA001 %'";

无论我尝试什么，我只是得到错误，我似乎无法解决我需要放在哪里。

任何伟大的伟大，非常感谢。

Answer 1

试试这个

//按区域过滤

create table t( id int,  answer varchar(10),Area varchar(10));
insert into t select 1  ,  'pass' , 'Area1';
insert into t select 2  ,  'pass' , 'Area1';
insert into t select 3  ,  'fail' , 'Area1';
insert into t select 4  ,  'fail' , 'Area1';
insert into t select 5  ,  'fail' , 'Area1';
insert into t select 6 ,   'fail' , 'Area2';

SELECT 
        (x.TotalFailedAnswerRecord * 100) /y.TotalRecord AS Fail_percent
FROM
            (   SELECT Area,TotalFailedAnswerRecord = COUNT(answer) 
                FROM t 
                WHERE answer='fail' AND Area = 'Area1' 
                GROUP BY Area
            )x
INNER JOIN
            (   SELECT Area,TotalRecord = COUNT(answer) 
                FROM t 
                WHERE Area = 'Area1'
                GROUP BY Area
            )y ON x.Area =y.Area

//Result
Fail_percent
-------------
60

//按区域，产品

过滤

create table t( id int,  answer varchar(10),Area varchar(10),Product varchar(10));
insert into t select 1  ,  'pass' , 'Area1' ,'Product1';
insert into t select 2  ,  'fail' , 'Area1' ,'Product1';
insert into t select 3  ,  'fail' , 'Area1' ,'Product1';
insert into t select 4  ,  'fail' , 'Area1' ,'Product1';
insert into t select 5  ,  'fail' , 'Area1' ,'Product2';
insert into t select 6 ,   'fail' , 'Area2' ,'Product2';

SELECT 
        (x.TotalFailedAnswerRecord * 100) /y.TotalRecord AS Fail_percent
FROM
            (   SELECT Area,Product,TotalFailedAnswerRecord = COUNT(answer) 
                FROM t 
                WHERE answer='fail' AND Area = 'Area1' AND Product = 'Product1' 
                GROUP BY Area,Product
            )x
INNER JOIN
            (   SELECT Area,Product,TotalRecord = COUNT(answer) 
                FROM t 
                WHERE Area = 'Area1' AND Product = 'Product1'
                GROUP BY Area,Product
            )y ON x.Area =y.Area AND x.Product = y.Product

//Result
Fail_percent
-------------
75

希望这有帮助

在MYSQL查询中使用变量计算

1 个答案: