Question

我正在尝试对URL中的page参数进行分页（而不是GET参数）。我还希望我的分页能够在多个不同的模板中共享代码。

鉴于此，我认为我需要做这样的事情：

urls.py：

url(r'^alias/page;(?P<page>[0-9]+)/(?P<id>.*)$', alias.get, name="alias"),

tempaltes / alias.html：

<div>...stuff...</div>
{% include "paginator.html" %}

templates / paginator.html：

{% if page_obj.has_previous or page_obj.has_next %}
{% load filters %}
<div class="pagination clear">
    {% if page_obj.has_previous %}
        <a href="{% url somemagic %}" class="prev">&lsaquo;&lsaquo; previous</a>
...

什么是somemagic？

假设除了设置页面page_obj.previous_page_number

之外，我想保持我的网址相同

Answer 1

修改

您需要 somemagic 作为具有当前视图名称的变量。

试试这个：

{% with request.path_info|resolve_url_name as current_view %} {% url current_view page_obj.previous_page_number object.id %} {% endwith %}

你可以使用django-snippets的一些代码来实现这个目的：

Variable resolving URL template tag使{％url％}标记从上下文中解析变量。

Resolve URLs to view name函数resolve_to_name(path)返回path的视图名称。您只需要创建一个使用此功能的过滤器。

此解决方案不适用于以下网址：

'alias/param1_regexp/param2_regexp/page;(?P<page>[0-9]+)/(?P<id>.*)$'

因为你对param1和param2一无所知。

可以对上面的django-snippets进行修改，以使这种网址有效：

第一个代码段修改：

from django.template import defaulttags, VariableDoesNotExist, Variable class ResolvingURLNode(defaulttags.URLNode): def render(self, context): original_view_name = self.view_name try: resolved = Variable(self.view_name).resolve(context) if len(resolved) > 1: self.view_name = resolved[0] if resolved[1]: self.args = [Variable(arg) for arg in resolved[1]] elif len(resolved) > 0: self.view_name = resolved[0] else: self.view_name = resolved except VariableDoesNotExist: pass ret = super(defaulttags.URLNode, self).render(context) # restore view_name in case this node is reused (e.g in a loop) in # which case the variable might resolve to something else in the next iteration) self.view_name = original_view_name return ret defaulttags.URLNode = ResolvingURLNode

第二段代码修改

from django.core.urlresolvers import RegexURLResolver, RegexURLPattern, Resolver404, get_resolver __all__ = ('resolve_to_name',) def _pattern_resolve_to_name(self, path): match = self.regex.search(path) if match: name = "" if self.name: name = self.name elif hasattr(self, '_callback_str'): name = self._callback_str else: name = "%s.%s" % (self.callback.__module__, self.callback.func_name) if len(match.groups()) > 0: groups = match.groups() else: groups = None return name, groups def _resolver_resolve_to_name(self, path): tried = [] match = self.regex.search(path) if match: new_path = path[match.end():] for pattern in self.url_patterns: try: resolved = pattern.resolve_to_name(new_path) if resolved: name, groups = resolved else: name = None except Resolver404, e: tried.extend([(pattern.regex.pattern + ' ' + t) for t in e.args[0 ['tried']]) else: if name: return name, groups tried.append(pattern.regex.pattern) raise Resolver404, {'tried': tried, 'path': new_path} # here goes monkeypatching RegexURLPattern.resolve_to_name = _pattern_resolve_to_name RegexURLResolver.resolve_to_name = _resolver_resolve_to_name def resolve_to_name(path, urlconf=None): return get_resolver(urlconf).resolve_to_name(path)

基本上，resolve_to_name返回视图的名称及其参数作为元组， new {% url myvar %}接受此元组并使用它来反转视图名称的路径，它是参数。

如果您不喜欢过滤器方法，也可以使用自定义中间件来完成。

上一个回答

你应该检查django-pagination，它是一个非常好的django应用程序，易于使用并完成工作。

使用django分页，对可迭代分页的代码将是：

{% load pagination_tags %}

{% autopaginate myiterable 10 %} 

{% for item in myiterable %} RENDERING CONTENT {% endfor %}

{% paginate %} 

myiterable 可以是任何可迭代的：list，tuple，queryset等

googlecode的项目页面： http://code.google.com/p/django-pagination/

Answer 2

它将类似于以下内容。除了我不知道id是什么意思所以我只是放了一个通用的对象id。 url的语法是{％url view_name param1 param2 ...％}

{% url alias page_obj.previous_page_number object.id %}

根据您的需要更新：

{% url alias page_obj.previous_page_number object.id as prev_url %}
{% include "paginator.html" %}
...
{% if page_obj.has_previous %}
        <a href="{{prev_url}}" class="prev">&lsaquo;&lsaquo; previous</a>

Django：你怎么能得到当前的URL标记名（用于分页）？

2 个答案: