Question

我需要编组json和xml输出。但是，如何在Spring中使用MOXy JAXB生成JSON输出？我可以生成xml文件，如示例中所示：http://wiki.eclipse.org/EclipseLink/Examples/MOXy/Spring/JAXBDynamicOXM

该文档没有输出json的任何示例。我知道我可以使用JAXB Marshaller通过设置jaxb属性来生成json输出。如何使用MOXy / Spring / JAXB做同样的事情？

感谢您的帮助！

Answer 1

注意：我是EclipseLink JAXB (MOXy)主管，是JAXB (JSR-222)专家组的成员。

以下答案基于MOXy wiki的示例：

http://wiki.eclipse.org/EclipseLink/Examples/MOXy/Spring/JAXBDynamicOXM

<强>的EclipseLink-oxm.xml

通常，JAXB / MOXy与静态域模型一起使用。在您排列的示例中，没有真实的模型，所有元数据都是通过MOXy的元数据文件提供的。

<?xml version="1.0" encoding="US-ASCII"?>
<xml-bindings xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm" package-name="example.gettingstarted">
    <java-types>
        <java-type name="Customer">
            <xml-root-element/>
            <java-attributes>
                <xml-element java-attribute="name" type="java.lang.String" xml-path="personal-info/name/text()" />
                <xml-element java-attribute="address" type="example.gettingstarted.Address" xml-path="contact-info/address" />
                <xml-element java-attribute="phoneNumbers" type="example.gettingstarted.PhoneNumber" container-type="java.util.ArrayList" xml-path="contact-info/phone-number" />
            </java-attributes>
        </java-type>
        <java-type name="PhoneNumber">
            <java-attributes>
                <xml-attribute java-attribute="type" type="java.lang.String"/>
                <xml-value java-attribute="value" type="java.lang.String"/>
            </java-attributes>
        </java-type>
        <java-type name="Address">
            <xml-root-element/>
            <java-attributes>
                <xml-element java-attribute="street" type="java.lang.String" xml-path="street/text()" />
                <xml-element java-attribute="city" type="java.lang.String" xml-path="city/text()" />
            </java-attributes>
        </java-type>
    </java-types>
</xml-bindings>

的 jaxb.properties

要在动态模型中使用MOXy，您需要指定一个不同于正常的jaxb.properties文件：

javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.dynamic.DynamicJAXBContextFactory

<强>演示

在下面的示例中，我们将XML文档转换为动态模型，然后将其封送到JSON。请注意，上下文路径（本示例中为“forum12162216”）必须与包含jaxb.properties文件的包名称相对应。通过在"eclipselink.media-type"上设置Marshaller属性来启用JSON绑定。

package forum12162216; import java.io.File; import java.util.*; import javax.xml.bind.*; import org.eclipse.persistence.dynamic.DynamicEntity; import org.eclipse.persistence.jaxb.JAXBContextProperties; import org.eclipse.persistence.jaxb.MarshallerProperties; public class Demo { public static void main(String[] args) throws Exception { Map<String, Object> properties = new HashMap<String, Object>(1); properties.put(JAXBContextProperties.OXM_METADATA_SOURCE, "forum12162216/eclipselink-oxm.xml"); JAXBContext jc = JAXBContext.newInstance("forum12162216", Demo.class.getClassLoader(), properties); Unmarshaller unmarshaller = jc.createUnmarshaller(); File xml = new File("src/forum12162216/customer.xml"); DynamicEntity customer = (DynamicEntity) unmarshaller.unmarshal(xml); Marshaller marshaller = jc.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); marshaller.setProperty(MarshallerProperties.MEDIA_TYPE, "application/json"); marshaller.marshal(customer, System.out); } }

<强> customer.xml

<?xml version="1.0" encoding="UTF-8"?> <customer> <personal-info><name>Jane Doe</name></personal-info> <contact-info> <address> <city>My Town</city> <street>123 Any Street</street> </address> <phone-number type="work">613-555-1111</phone-number> <phone-number type="cell">613-555-2222</phone-number> </contact-info> </customer>

<强>输出

{ "customer" : { "personal-info" : { "name" : "Jane Doe" }, "contact-info" : { "address" : { "street" : "123 Any Street", "city" : "My Town" }, "phone-number" : [ { "type" : "work", "value" : "613-555-1111" }, { "type" : "cell", "value" : "613-555-2222" } ] } } }

了解更多信息

http://blog.bdoughan.com/2011/08/binding-to-json-xml-geocode-example.html

在Spring中使用MOXy JAXB生成JSON输出

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