Question

我在我的应用程序中使用postgresql-8.3-603.jdbc4.jar和jdk 1.6进行数据库操作。我有时会得到以下异常，并且重启有助于暂时避免这种异常。

org.postgresql.util.PSQLException：在此ResultSet中找不到列名sender_id。 at org.postgresql.jdbc2.AbstractJdbc2ResultSet.findColumn（AbstractJdbc2ResultSet.java:2502） at org.postgresql.jdbc2.AbstractJdbc2ResultSet.getString（AbstractJdbc2ResultSet.java:2345）在org.apache.commons.dbcp.DelegatingResultSet.getString（DelegatingResultSet.java:225）在org.apache.commons.dbcp.DelegatingResultSet.getString（DelegatingResultSet.java:225）在com.netcore.bulkrequest.db.FeedDAO.setFeedDetails（FeedDAO.java:142）在com.netcore.bulkrequest.feed.Feed.getInstance（Feed.java:37）在com.netcore.bulkrequest.core.BulkRequestTask。（BulkRequestTask.java:86） at com.netcore.bulkrequest.core.BulkRequestValidate.getBulkRequestTaskObject（BulkRequestValidate.java:104）在com.netcore.bulkrequest.core.BulkRequestValidate.run（BulkRequestValidate.java:57） at java.util.concurrent.ThreadPoolExecutor $ Worker.runTask（ThreadPoolExecutor.java:886） at java.util.concurrent.ThreadPoolExecutor $ Worker.run（ThreadPoolExecutor.java:908）在java.lang.Thread.run（Thread.java:619）

以下是代码段：

公共类FeedDAO { / ** *数据库连接池对象 * / private final DBContext dbc;

private final Feed feed;

public static final String SENDER_ID_ATTRIBUTE = "sender_id";

/**
 * Constructor
 * 
 * @param dbc
 * @param feed
 */
public FeedDAO(DBContext dbc, Feed feed) {
    this.dbc = dbc;
    this.feed = feed;
}

public void setFeedDetails（）抛出SQLException {

    String feedDetailsQuery = "SELECT a.priority, b.keyword, b.welcome " +
            "   FROM feed AS a, pub_feed_info AS b " +
            "   WHERE a.resource_id = b.resource_id AND b.resource_id = ?";

    String senderIdQuery = "SELECT b.attribute_value AS " +
            SENDER_ID_ATTRIBUTE + " FROM " +
            "attribute_master AS a, feed_attributes AS b " +
            "WHERE a.attribute_id = b.attribute " +
            "   AND a.attribute_name='" + SENDER_ID_ATTRIBUTE + "' " +
            "   AND feed_id = ?";

    Connection con = null;
    PreparedStatement fdStmt = null;
    PreparedStatement siStmt = null;

    try {
        con = dbc.getConnection();

        //Get the feed details
        fdStmt = dbc.getPreparedStatement(con, feedDetailsQuery);

        fdStmt.setInt(1, this.feed.getFeedId());
        fdStmt.execute();

        ResultSet fdResults = fdStmt.getResultSet();

        while (fdResults.next()) {
            String keyword = fdResults.getString("keyword");
            String welcomeMsg = fdResults.getString("welcome");
            int priority = fdResults.getInt("priority");

            if(null != keyword) {
                this.feed.setKeyword(keyword);
            } else {
                this.feed.setKeyword(String.valueOf(this.feed.getFeedId()));
            }
            this.feed.setWelcomeMsg(welcomeMsg);
            this.feed.setPriority(priority);
        }

        //Get the sender id
        siStmt = dbc.getPreparedStatement(con, senderIdQuery);
        siStmt.setInt(1, this.feed.getFeedId());

        if(siStmt.execute()) {
            ResultSet siResults = siStmt.getResultSet();

            while(siResults.next()) {
                String senderId = siResults.getString(SENDER_ID_ATTRIBUTE);

                this.feed.setSenderId(senderId);
            }

        } else {
            this.feed.setSenderId(Feed.DEFAULT_SENDER_ID);
        }

    } catch (SQLException ex) {
        throw ex;
    } finally {
        if (fdStmt != null) { fdStmt.close(); }
        if (siStmt != null) { siStmt.close(); }
        if (con  != null) { con.close(); }
    }
}

}

任何人都可以帮我找到永久性修复方法吗？

谢谢，摩尼

Answer 1

错误的关键部分是“在此ResultSet中找不到列名sender_id” - 第一行。那么，如何向我们展示正在寻找一个不存在的列的查询，以及在pgsql中交互式执行该查询的结果，模式的相关部分等等？当然，你不能指望我们在没有看到异常回溯的情况下帮助你进行调试，没有关于你的代码和数据库的线索！

PgSQL异常：找不到列名

1 个答案: