Question

我希望在一个语句中添加两个值，而我目前对如何解决此问题感到茫然，这应该是我的陈述应该很简单：

 SELECT COUNT(UserModified) as SecondTally
 FROM JobAgents 
 WHERE UserModified = 1

然后从下面的这个值中减去上面的值。

 SELECT SUM(EmailsSent) as FirstTally
 FROM JobAgentEmails
 WHERE Date BETWEEN '7/1/2012 12:00:00 AM' AND '7/31/2012 11:59:59 PM'

对此的任何帮助将不胜感激。非常感谢。

Answer 1

最简单的方法是简单地将结果与两个子查询相结合，这两个子查询可以存储在变量中，也可以简单地组合在一个查询中，如下所示：

SELECT
  (SELECT SUM(EmailsSent) as FirstTally
   FROM JobAgentEmails
   WHERE Date BETWEEN '7/1/2012 12:00:00 AM' AND '7/31/2012 11:59:59 PM')
- (SELECT COUNT(UserModified) as SecondTally
   FROM JobAgents 
   WHERE UserModified = 1)

Answer 2

您可以使用交叉连接来实现此目的，将值集中在一起：

select jae.FirstTallyl - ja.SecondTally
from (SELECT COUNT(UserModified) as SecondTally
      FROM JobAgents
      WHERE UserModified = 1
     ) ja cross join
     (SELECT SUM(EmailsSent) as FirstTally
      FROM JobAgentEmails
      WHERE Date BETWEEN '7/1/2012 12:00:00 AM' AND '7/31/2012 11:59:59 PM'  
    ) jae

Answer 3

这是一种方式：

DECLARE @FirstTally int;
DECLARE @SecondTally int;

SELECT @SecondTally = COUNT(UserModified) 
 FROM JobAgents 
 WHERE UserModified = 1

 SELECT @FirstTally = SUM(EmailsSent) 
 FROM JobAgentEmails
 WHERE Date BETWEEN '7/1/2012 12:00:00 AM' AND '7/31/2012 11:59:59 PM'


SELECT @FirstTalley - @SecondTalley AS Result

Answer 4

 select 
 (SELECT SUM(EmailsSent) as FirstTally
 FROM JobAgentEmails
 WHERE Date BETWEEN '7/1/2012 12:00:00 AM' AND '7/31/2012 11:59:59 PM')
 -

 (SELECT COUNT(UserModified) as SecondTally
 FROM JobAgents 
 WHERE UserModified = 1)

 AS 'result';

在SQL Server中添加两个值

4 个答案: