Question

我正在使用Amazon Simple Email Service java API向接收者发送邮件。我在标签内的邮件正文中发送URL。我的用例要求用户双击收到的URL以提示某些操作。（如确认邮件）

问题是url在接收时被编码。双击它会发现页面未找到（404）错误。

原始网址：http://something.com/confirm/email=abc@hotmail.com&regKey=somekey&confirm=true 当我在邮件上双击此URL时，链接将在地址栏中打开，如下所示： http://something.com/confirm/email=abc%40hotmail.com%26regKey=somekey%26confirm=true

我正在使用 AmazonSimpleEmailServiceClient 。代码如下：

    SendEmailRequest request = new SendEmailRequest().withSource(sourceAddress);

String confirmationURL="http://something.com/confirm/email=abc@hotmail.com&regKey=somekey&confirm=true";

            List<String> toAddresses = new ArrayList<String>();
            toAddresses.add(toEmail);

            Destination dest = new Destination().withToAddresses(toAddresses);
            request.setDestination(dest);

            Content subjContent = new Content().withData("Confirmation Request");
            Message msg = new Message().withSubject(subjContent);

            // Include a body in both text and HTML formats
            Content textContent = new Content().withData("Dear please go to the following URL:"+
                    confirmationURL+"\n\n");

            Content htmlContent = new Content().withData("<p>Dear please go to the following URL:</p>"+
                    "<p><a href=\""+confirmationURL+"\">"+confirmationURL+"</a></p>");

             Body body = new Body().withHtml(htmlContent).withText(textContent);
            msg.setBody(body);
            request.setMessage(msg)

更新

刚刚发现，只有当收件人电子邮件位于 hotmail.com 时才会出现此问题。为什么微软总是要做一些不同的事情？有人帮忙！

Answer 1

使用java.net.URLEncoder类：

String confirmationURL = URLEncoder.encode( "http://something.com/confirm/email=abc@hotmail.com&regKey=somekey& confirm=true", "UTF-8");

如何在没有编码的情况下发送邮件中的URL

1 个答案: