如何在Perl中创建嵌套哈希作为常量?

时间:2009-07-31 19:54:29

标签: perl hash constants perl-data-structures

我想在Perl中使用以下Ruby代码:

class Foo
  MY_CONST = {
    'foo' => 'bar',
    'baz' => {
      'innerbar' => 'bleh'
    },
  }

  def some_method
    a = MY_CONST[ 'foo' ]
  end

end

# In some other file which uses Foo...

b = Foo::MY_CONST[ 'baz' ][ 'innerbar' ]

也就是说,我只想声明一个常量的嵌套哈希结构,以便在类和外部使用。怎么样?

4 个答案:

答案 0 :(得分:11)

您也可以使用内置完成:

package Foo;
use constant MY_CONST =>
{
    'foo' => 'bar',
    'baz' => {
        'innerbar' => 'bleh',
    },
};

sub some_method
{
    # presumably $a is defined somewhere else...
    # or perhaps you mean to dereference a parameter passed in?
    # in that case, use ${$_[0]} = MY_CONST->{foo} and call some_method(\$var);
    $a = MY_CONST->{foo};
}

package Main;  # or any other namespace that isn't Foo...
# ...
my $b = Foo->MY_CONST->{baz}{innerbar};

答案 1 :(得分:8)

您可以使用Hash::Util模块锁定和解锁哈希值(键,值或两者)。

package Foo;
use Hash::Util;

our %MY_CONST = (
    foo => 'bar',
    baz => {
        innerbar => 'bleh',
    }
);

Hash::Util::lock_hash_recurse(%MY_CONST);

然后在其他文件中:

use Foo;
my $b = $Foo::MY_CONST{baz}{innerbar};

答案 2 :(得分:4)

请参阅Readonly

#!/usr/bin/perl

package Foo;

use strict;
use warnings;

use Readonly;

Readonly::Hash our %h => (
    a => { b => 1 }
);

package main;

use strict;
use warnings;

print $Foo::h{a}->{b}, "\n";

$h{a}->{b} = 2;

输出:

C:\Temp> t
1
Modification of a read-only value attempted at C:\Temp\t.pl line 21

答案 3 :(得分:1)

这是perl中哈希的指南。 Hash of Hashes