Question

我收到了上述错误。我在C编码并使用标准的gcc编译器（命令窗口）。这是我的代码中有问题的部分。我没有看到任何错误，也许我的眼睛厌倦了看同样的事情

LEADER *call_leader(double st1, double st2, double incentive, double pdis)
{
    LEADER *leader= (LEADER *)malloc(sizeof(LEADER));
    double shortest = MIN(st1, st2) ; //shortest station
    if (shortest == st1 && s1 != 0){ //no congestion
        leader->price1 = p_max;
        leader->price2 = p_max;
    }

    if (shortest == st2 && s2 != 0){ //no congestion
        leader->price1 = p_max;
        leader->price2 = p_max;
    }

    if (shortest == st1 && s1 == 0){ //congestion at station 1
        if (s2 != 0){ // no congestion at station 2, try to route
            leader->price1 = p_max;
            double cost_1 = shortest*pdrive + p_max;
            double p2 = cost1 - st2*pdrive - (sqrt(pow((st2 - st1),2)))*pdis -     incentive;
        if (p2 >= p_min){
            leader->price2 = p2;
        }else{
            leader->price2 = p_min;
        }
    }
    else if (s2 == 0){
        if (r1 >= r2){ // st1 less congestion
            leader-> price1 = p_max;
        }
Problematic Line =>     else (r1 < r2) {   //try to route s2
            leader -> price1 = p_max;
            double cost_1 = shortest*pdrive + p_max;
            double p2 = cost1 - st2*pdrive - (sqrt(pow((st2 - st1),2)))*pdis - incentive;
            if (p2 >= p_min){
                leader->price2 = p2;
            }
            else{
                leader->price2 = p_min;
            }
        } 

    }
}

Answer 1

... else if (r1 < r2) ...将是声明的条件形式，但由于if具有互补条件(r1 >= r2)，因此简单else就可以了。

所以你会：

if (r1 >= r2){
    leader-> price1 = p_max;
}
else {
    leader -> price1 = p_max;
...

Answer 2

尝试更改

else (r1 < r2) {   //try to route s2

到

else if (r1 < r2) {   //try to route s2

Answer 3

您不需要else的条件。当所有if的条件都失败时执行它。如果括号删除东西，你会没事的。：

else {
...

预期';'在'{'令牌C代码之前

3 个答案: