我使用gen_tcp套接字有以下代码,它应该使用{active, true}
一些总是大小为5的二进制命令(例如Command = <<"hello">>
)
{ok, ListenSocket} = gen_tcp:listen(5555, [{active, true}, {mode, binary},
{packet, 0}]),
{ok, Socket} = gen_tcp:accept(ListenSocket),
loop().
receive() ->
{tcp, _Socket, Message:4/binary} ->
io:format("Success~n", []),
loop();
{tcp, _Socket, Other} ->
io:format("Received: ~p~n", [Other]),
loop()
end.
但是如果我尝试像这样的客户端连接:
1> {ok, S} = gen_tcp:connect("localhost", 5555, []).
{ok,#Port<0.582>}
2> gen_tcp:send(S, <<"hello">>).
ok
我在接收部分:
Received: {tcp,#Port<0.585>,<<"hello">>}
所以我想我的错误是在模式匹配中...但在哪里?
答案 0 :(得分:2)
您的receive
子句看起来不正确,应该是:
{tcp, _Socket, <<Message:5/binary>>} ->
....
答案 1 :(得分:0)
据我了解,您需要gen_tcp:recv
功能。来自文档:
recv(Socket, Length) -> {ok, Packet} | {error, Reason}
在您的代码中,它将类似于:
...
{ok, Socket} = gen_tcp:accept(ListenSocket),
loop(Socket).
loop(Socket) ->
case gen_tcp:recv(Socket, 5) of
{ok, Data} ->
io:format("Success~n", []),
loop(Socket);
{error, closed} ->
ok
end.