我有一系列要返回的哈希值。
在返回数组之前我交叉检查它。它工作正常。
但是在将hashess数组返回给调用子后,我无法读取它。
plz找到以下代码参考..并让我知道如何读取/返回哈希数组
谢谢...:)
#!/usr/bin/perl
use strict;
use warnings;
# Subroutine prototypes
sub get_two_arrays();
my @one=();
@one = get_array_Hashes();
print "\n First: @one->{Version}\n"; // Printing the return array of hashes
sub get_array_Hashes() {
my @dotNetHashArray =();
my $dotNetHash1 = {Version => "Test-1 Version", SP => "installedSp", Build => "installedBuild"};
push @dotNetHashArray, $dotNetHash1;
my $dotNetHash2 = {Version => "Test-2 Version", SP => "installedSp", Build => "installedBuild"};
push @dotNetHashArray, $dotNetHash2;
my $dotNetHash3 = {Version => "Test-3 Version", SP => "installedSp", Build => "installedBuild"};
push @dotNetHashArray, $dotNetHash3;
print "Test Array of hashes before return";
for(my $i=0; $i<@dotNetHashArray; $i++)
{
print("\n Hash Value : ".$dotNetHashArray[$i]->{Version});
}
return \@dotNetHashArray
}
答案 0 :(得分:2)
Perl不是C,原型是针对非常不同和特殊的东西。如果你不知道他们服务的利基目的,那么从不使用它们
同样,在调用子程序之前没有理由预先声明子程序。只要您不使用原型,Perl就会做正确的事情
如果要将数组声明为空,则也没有理由初始化数组。这就是Perl默认做的事情
熟悉Perl的人会感谢您为变量和子例程使用小写和下划线标识符。 Camel案例通常保留用于包名称
正如其他人所说,您将引用返回到数组。但是,如果您将其作为参考并将其作为参考使用,则可能更好地取消引用返回值。唯一必要的更改是迭代返回的数组
这是您的计划的更规范形式,我希望能帮助
use strict;
use warnings;
my $one = get_array_Hashes();
print "\nArray of hashes after return\n";
print "First: $_->{Version}\n" for @$one;
sub get_array_Hashes {
my @dotnet_hash_array;
my $dotnet_hash1 = {
Version => "Test-1 Version",
SP => "installedSp",
Build => "installedBuild"
};
push @dotnet_hash_array, $dotnet_hash1;
my $dotnet_hash2 = {
Version => "Test-2 Version",
SP => "installedSp",
Build => "installedBuild"
};
push @dotnet_hash_array, $dotnet_hash2;
my $dotnet_hash3 = {
Version => "Test-3 Version",
SP => "installedSp",
Build => "installedBuild"
};
push @dotnet_hash_array, $dotnet_hash3;
print "Test Array of hashes before return\n";
for my $i (0 .. $#dotnet_hash_array) {
print "Hash Value : $dotnet_hash_array[$i]->{Version}\n";
}
return \@dotnet_hash_array
}
<强>输出强>
Test Array of hashes before return
Hash Value : Test-1 Version
Hash Value : Test-2 Version
Hash Value : Test-3 Version
Array of hashes after return
First: Test-1 Version
First: Test-2 Version
First: Test-3 Version
答案 1 :(得分:1)
您正在返回对数组的引用:
return \@dotNetHashArray
你必须
@one = @{ get_array_Hashes() };
取消引用它。
另外
//
评论不起作用(使用#
)
通常您不需要在Perl中使用原型(参见Why are Perl 5's function prototypes bad?)
在返回后还需要一个循环来打印出值
您不需要游标变量来迭代Perl中的数组
for my $item (@dotNetHashArray) {
print "\n Hash Value: $item->{Version}";
}
如果您需要在打印开头设置\n
,那么在循环之后您将错过\n
你最终会得到:
#!/usr/bin/perl
use strict;
use warnings;
# do not use function prototypes
# perl subroutines are usually all lowercase (no camel-case)
sub get_array_hashes {
my @dot_net_hash_array = ();
# actually you don't need to create a local variable for each item you push
push @dot_net_hash_array, {
# avoid unncessary string interpolation (use ' if no variables in the string have to be interpolated)
version => 'Test-1 Version',
sp => 'installedSp',
build => 'installedBuild'
};
push @dot_net_hash_array,
{
version => 'Test-2 Version',
sp => 'installedSp',
build => 'installedBuild'
};
push @dot_net_hash_array,
{
version => 'Test-3 Version',
sp => 'installedSp',
build => 'installedBuild'
};
print "Test Array of hashes before return\n";
for my $item (@dot_net_hash_array) {
print "Hash Value : $item->{version}\n";
}
return \@dot_net_hash_array;
}
my @one = @{ get_array_hashes() };
# Use # for comments
# Printing the return array of hashes
print "Test Array of hashes after return\n";
for my $item (@one) {
print "Hash Value : $item->{version}\n";
}