Question

我有一组值会定期更新。更新阵列时，我想使用更新后的数组中的新值执行操作。

$old_node->field_name[0]['value'] = 'red'
$old_node->field_name[1]['value'] = 'yellow'
$old_node->field_name[2]['value'] = 'blue'


$updated_node->field_name[0]['value'] = 'green',
$updated_node->field_name[1]['value'] = 'red',
$updated_node->field_name[2]['value'] ='purple',
$updated_node->field_name[3]['value'] = 'blue',

因此'green'和'purple'的值是新数组中的新值。我需要通过函数运行ADDED中的每个值到新数组。类似的东西：

foreach(of the newly added values that are in the new array){
 //do stuff;
}

更新阵列时可能会删除某些值，因此key =＆gt;值对可能会更改。

我试过了：

foreach($updated_node->field_name as $new_value){
    if(!in_array($new_value['value'], $old_node->field_name) && $new_value['value'] !== NULL){

    //Do stuff; 

        } 
    }

但这不起作用。我也尝试使用array_diff和array_intersect选择新值，但这也不起作用。

Answer 1

使用array_diff()

$old_array = array(
          0 => 'red',
          1 =>'yellow',
          2 => 'blue'
);

$new_array = array(
          0 => 'green',
          1 => 'red',
          2 =>'purple',
          4 => 'blue'
);

$diff = array_diff($new_array, $old_array);

print_r($diff);

/*
Array
(
    [0] => green
    [2] => purple
)
*/

获取新代码

$old_node->field_name[0]['value'] = 'red';
$old_node->field_name[1]['value'] = 'yellow';
$old_node->field_name[2]['value'] = 'blue';


$updated_node->field_name[0]['value'] = 'green';
$updated_node->field_name[1]['value'] = 'red';
$updated_node->field_name[2]['value'] = 'purple';
$updated_node->field_name[3]['value'] = 'blue';

$diff = array();
foreach($updated_node->field_name as $num => $field){
    $tmpval = false;
    foreach($old_node->field_name as $old){
        if($field['value'] == $old['value']){
            $tmpval = true;
        }
    }
    if(!$tmpval){
        $diff[$num] = $field['value'];    
    }
}

print_r($diff);

/*
Array
(
    [0] => green
    [2] => purple
)
*/

Answer 2

$old_array = array(
          [0] => 'red',
          [1] =>'yellow',
          [2] => 'blue',
);

$new_array = array(
          [0] => 'green',
          [1] => 'red',
          [2] =>'purple',
          [4] => 'blue',
);

$diff = array_diff($new_array, $old_array);
var_dump($diff);

导致

array(2) {
  [0]=>
  string(5) "green"
  [2]=>
  string(6) "purple"
}

这是正确的（预期）结果。

Answer 3

这是一个简单函数，用于加载两个带有添加和删除值的数组：

function loadArrayDifferences($before, $after, &$added, &$removed) {
    $added = array_diff($after, $before);
    $removed = array_diff($before, $after);
}

这是一个测试脚本：

<?php

$ar1 = array(
'one',
'two',
'three',
'four'  

);
$ar2 = array(
'two',
'four',
'six',
'eight',    
);

$adds = array();
$rems = array();
loadArrayDifferences($ar1, $ar2, $adds, $rems);
var_dump($adds);
var_dump($rems);

function loadArrayDifferences($before, $after, &$added, &$removed) {
    $added = array_diff($after, $before);
    $removed = array_diff($before, $after);
}

输出：

array(2) {
  [2]=>
  string(3) "six"
  [3]=>
  string(5) "eight"
}
array(2) {
  [0]=>
  string(3) "one"
  [2]=>
  string(5) "three"
}

检查新旧数组PHP之间的不同值

3 个答案: