Question

这是test.php

<?php

include("../includes/database.php");
$db = new Database();
$sql = "SELECT * FROM users WHERE username='mr.man' ";
$db->query($sql);
$db->singleRecord(); //call this if the query will only return a single row 
echo $db->Record['password']; // use the field name for example or; 
echo $db->Record[0]; //use indexes
echo "test";

这是database.php

class Database{
private $Host     ="localhost";    // Hostname of our MySQL server.
private $Database ="admin_db";  // Logical database name on that server.
private $User     ="user";             // User and Password for login.
private $Password ="xxx";
private $Link_ID  = 0;                  // Result of mysql_connect().
private $Query_ID = 0;                  // Result of most recent mysql_query().
private $Record = array();            // current mysql_fetch_array()-result.
private $Row;                           // current row number.
private $LoginError = "";
private $Errno    = 0;                  // error state of query...
private $Error    = "";
} // end class Database

我删除了类中的函数以获取我收到的PHP解析错误的根目录。我检查过我结束了陈述;并且还有匹配的“。我仍然不明白我收到的原因：

解析错误：语法错误，意外T_STRING，期待第4行/var/www/vhosts/example.com/httpdocs/includes/database.php中的T_FUNCTION

Answer 1

用var替换private（这不是Javascript）：

class Database{
    private $Host     ="localhost";    // Hostname of our MySQL server.
    private $Database ="admin_db";  // Logical database name on that server.
    private $User     ="user";             // User and Password for login.
    private $Password ="xxx";
    private $Link_ID  = 0;                  // Result of mysql_connect().
    private $Query_ID = 0;                  // Result of most recent mysql_query().
    private $Record = array();            // current mysql_fetch_array()-result.
    private $Row;                           // current row number.
    private $LoginError = "";
    private $Errno    = 0;                  // error state of query...
    private $Error    = "";
} // end class Database

在包含PHP的类中解析错误

1 个答案: