Question

我有两个数组，我需要显示array1没有的数组，反之亦然。

string[] a = { "hello", "momo" }
string[] b = { "hello"}

输出：

momo

我正在使用.Except并尝试在消息框中显示输出，但是当我执行我的代码时，输出是这样的：

System.Linq.Enumerable+<ExceptIterator>d_99'1[System.Char]

我的代码：

//Array holding answers to test
string[] testAnswer = new string[20] { "B", "D", "A", "A", "C", "A", "B", "A", "C", "D", "B", "C", "D", "A", "D", "C", "C", "B", "D", "A" };
string a = Convert.ToString(testAnswer);

//Reads text file line by line. Stores in array, each line of the file is an element in the array
string[] inputAnswer = System.IO.File.ReadAllLines(@"C:\Users\Momo\Desktop\UNI\Software tech\test.txt");
string b = Convert.ToString(inputAnswer);

//Local variables
int index = 0;
Boolean arraysequal = true;

if (testAnswer.Length != inputAnswer.Length)
{
    arraysequal = false;
}

while (arraysequal && index < testAnswer.Length)
{
    if (testAnswer[index] != inputAnswer[index])
    {
        arraysequal = false;
    }
    index++;
}

MessageBox.Show("" + a.Except(b));

Answer 1

你应该将它转换为字符串 - 否则，它是一个可枚举的，ToString不会产生预期的结果。

MessageBox.Show(string.Join(", ", a.Except(b)));

编辑此行中存在同样的问题：

string a = Convert.ToString(testAnswer);

你应该用

替换它

string a = String.Join(", ", testAnswer); // << You can use a different separator

Answer 2

a.Except(b)的类型为IEnumerable<string>，而MessageBox.Show()接受string。

所以你需要转换前两秒，例如：

string output = String.Join(", ", input)`

将用逗号分隔每个元素。

Except（）为两个数组提供了错误的输出？

2 个答案: