我必须在屏幕的不同点渲染相同的纹理三角形。我发现它渲染超过10次时会有很强的性能损失。如何在绘制之前多次渲染相同的纹理三角形。
我试图在绘制之前向顶点数组添加新几何图形但没有成功。我认为步幅值不对：
这是顶点和纹理坐标。我正在绘制2个纹理正方形，所以我只是复制数组中的数据。
在DrawArray中，我将4改为8.第一个方块似乎没问题，第二个方格肯定不好 GLES20.glDrawArrays（GLES20.GL_TRIANGLE_STRIP，0,8）;
private float[] mVertexData2 =
{
-0.3f, -0.3f, 0.0f, // V1 - bottom left
-0.3f, 0.3f, 0.0f, // V2 - top left
0.3f, -0.3f, 0.0f, // V3 - bottom right
0.3f, 0.3f, 0.0f // V4 - top right
//Seconde square
-1f, -1f, 0.0f, // V1 - bottom left
-1f, 1f, 0.0f, // V2 - top left
1f, -1f, 0.0f, // V3 - bottom right
1f, 1f, 0.0f // V4 - top right
};
private float[] mTextureData2 =
{
0.0f, 1.0f, // top left (V2)
0.0f, 0.0f, // bottom left (V1)
1.0f, 1.0f, // top right (V4)
1.0f, 0.0f, // bottom right (V3)
//Texture for seconde square
0.0f, 1.0f, // top left (V2)
0.0f, 0.0f, // bottom left (V1)
1.0f, 1.0f, // top right (V4)
1.0f, 0.0f, // bottom right (V3)
};
public void draw()
{
// Load the vertex position
mVertices.position(0);
GLES20.glVertexAttribPointer ( mSpritePositionLoc, 3, GLES20.GL_FLOAT,
false,
0, mVertices );
// Load the texture coordinate
mTexVertices.position(0);
GLES20.glVertexAttribPointer ( mSpriteTexCoordLoc, 2, GLES20.GL_FLOAT,
false,
0,
mTexVertices );
GLES20.glEnableVertexAttribArray ( mSpritePositionLoc );
//GLES20.glEnableVertexAttribArray ( mSpriteTexCoordLoc );
GLES20.glActiveTexture ( GLES20.GL_TEXTURE0 );
GLES20.glBindTexture ( GLES20.GL_TEXTURE_2D, mSpriteTextureId);
// Set the base map sampler to texture unit to 1
GLES20.glUniform1i ( mSpriteTextureIdLoc, 1 );
//GLES20.glDrawElements ( GLES20.GL_TRIANGLES, 6, GLES20.GL_UNSIGNED_SHORT, mIndices );
GLES20.glDrawArrays(GLES20.GL_TRIANGLE_STRIP , 0, 8);
}
答案 0 :(得分：1)
在每个纹理中，而不是使用DrawArrays，你需要保存它的顶点和纹理坐标，正确的旋转和平移到一个大数组，然后使用DrawArrays只绘制这个数组。（嗯...我不能更好地解释它:)）
这是我的代码：
float squarevData[12]={
-1,1,
1,1,
-1,-1,
1,1,
1,-1,
-1,-1,
};
float squarevData2[12]={
-1,1,
1,1,
-1,-1,
1,1,
1,-1,
-1,-1,
};
class BatchRenderer
{
public:
float* partVdata;
float* partCdata;
float* partTdata;
int counter1,counter2,counter3;
int count;
bool isz;
BatchRenderer(int maxTextures,bool iszi)
{
isz=iszi;
if(isz)partVdata=(float*)malloc(maxTextures*18*4);
else partVdata=(float*)malloc(maxTextures*12*4);
partCdata=(float*)malloc(maxTextures*24*4);
partTdata=(float*)malloc(maxTextures*12*4);
}
void Draw(float x,float y,float z,float scalex,float scaley,float angle,float r,float g,float b,float a)
{
angle*=0.017453f;
for(int c2=0;c2<12;c2+=2)
{
float x=squarevData[c2]*scalex;
float y=squarevData[c2+1]*scaley;
float cos1=cos(angle);
float sin1=sin(angle);
squarevData2[c2] = (cos1*x) - ( sin1*y);
squarevData2[c2+1] = (sin1*x) + ( cos1*y);
}
partVdata[counter1++]=x+squarevData2[0];
partVdata[counter1++]=y+squarevData2[1];
if(isz)partVdata[counter1++]=z;
partCdata[counter2++]=r;
partCdata[counter2++]=g;
partCdata[counter2++]=b;
partCdata[counter2++]=a;
partTdata[counter3++]=0;
partTdata[counter3++]=1;
partVdata[counter1++]=x+squarevData2[2];
partVdata[counter1++]=y+squarevData2[3];
if(isz)partVdata[counter1++]=z;
partCdata[counter2++]=r;
partCdata[counter2++]=g;
partCdata[counter2++]=b;
partCdata[counter2++]=a;
partTdata[counter3++]=1;
partTdata[counter3++]=1;
partVdata[counter1++]=x+squarevData2[4];
partVdata[counter1++]=y+squarevData2[5];
if(isz)partVdata[counter1++]=z;
partCdata[counter2++]=r;
partCdata[counter2++]=g;
partCdata[counter2++]=b;
partCdata[counter2++]=a;
partTdata[counter3++]=0;
partTdata[counter3++]=0;
partVdata[counter1++]=x+squarevData2[6];
partVdata[counter1++]=y+squarevData2[7];
if(isz)partVdata[counter1++]=z;
partCdata[counter2++]=r;
partCdata[counter2++]=g;
partCdata[counter2++]=b;
partCdata[counter2++]=a;
partTdata[counter3++]=1;
partTdata[counter3++]=1;
partVdata[counter1++]=x+squarevData2[8];
partVdata[counter1++]=y+squarevData2[9];
if(isz)partVdata[counter1++]=z;
partCdata[counter2++]=r;
partCdata[counter2++]=g;
partCdata[counter2++]=b;
partCdata[counter2++]=a;
partTdata[counter3++]=1;
partTdata[counter3++]=0;
partVdata[counter1++]=x+squarevData2[10];
partVdata[counter1++]=y+squarevData2[11];
if(isz)partVdata[counter1++]=z;
partCdata[counter2++]=r;
partCdata[counter2++]=g;
partCdata[counter2++]=b;
partCdata[counter2++]=a;
partTdata[counter3++]=0;
partTdata[counter3++]=0;
count++;
}
void RenderStart()
{
counter1=counter2=count=counter3=0;
}
void RenderStop(int textureid)
{
glEnable(GL_TEXTURE_2D);
glTexEnvf(GL_TEXTURE_ENV, GL_TEXTURE_ENV_MODE,GL_MODULATE);
glEnableClientState(GL_COLOR_ARRAY);
glEnableClientState(GL_TEXTURE_COORD_ARRAY);
glEnableClientState(GL_VERTEX_ARRAY);
glBindTexture(GL_TEXTURE_2D, textureid);
glTexCoordPointer(2, GL_FLOAT, 0, partTdata);
glColorPointer(4, GL_FLOAT, 0,partCdata );
if(isz)glVertexPointer(3, GL_FLOAT, 0, partVdata);
else glVertexPointer(2, GL_FLOAT, 0, partVdata);
glDrawArrays(GL_TRIANGLES, 0, count*6);
glDisableClientState(GL_COLOR_ARRAY);
glDisableClientState(GL_TEXTURE_COORD_ARRAY);
glDisableClientState(GL_VERTEX_ARRAY);
}
};
如何使用它？
BatchRenderer* br=new BatchRenderer(500,false)//the max number of textures that can be drawn , and if you want z axis
void Render()
{
br->RenderStart();
for(int c=0;c<POINTS;c++)
{
br->Draw(p[c].x,p[c].y,0,p[c].scalex,p[c].scaly,p[c].angle,p[c].r,p[c].g,p[c].b,p[c].a);
}
br->RenderStop(yourtextureid);
}
您可以使用mid设备以60 fps绘制超过500个纹理，并且每个
可以具有独特的比例，旋转和颜色