我有一个django问题。我想发送来自浏览器或业务逻辑的数据 在我的django服务器上到另一个django服务器或只是相同的服务器但不同的端口,来处理请求。我能怎么做?我试图使用套接字,但似乎没有用。
Following is my code: accept the client's request: def im(request): userp = None try: userp = UserProfile.objects.get(user = request.user) except: pass if not userp: return HttpResponse("error") print '111' if request.method == "GET": import json msg = json.loads(request.GET.get('msg')) try: msg['from_id'] = userp.id if msg.get('type', '') == 'sync': #页面同步消息 msg['to_id'] = userp.id push_msg(msg) return HttpResponse("success") except: return HttpResponse("error") #return HttpResponseRedirect("http://127.0.0.1:9000/on_message") return HttpResponse("error") helper.py:push_msg: def push_msg(msg): print '111' params = str(msg) headers = {"Content-type":"application/x-www-form-urlencoded", "Accept":"text/plain"} conn = httplib.HTTPConnection("http://127.0.0.1:9000/push_msg/") conn.request("POST", "/cgi-bin/query", params, headers) url(r'^push_msg/$', 'chat.events.on_message') events.py:on_message def on_message(request): msg = request.POST.get('msg') msg = eval(msg) try: print 'handle messages' from_id = int(msg['from_id']) to_id = int(msg['to_id']) user_to = UserProfile.objects.get(id = msg['to_id']) django_socketio.broadcast_channel(msg, user_to.channel) if msg.get('type', '') == 'chat': ct = Chat.objects.send_msg(from_id=from_id,to_id=to_id,content=data['content'],type=1) ct.read = 1 ct.save() except: pass
答案 0 :(得分:2)
使用python请求模块执行此请求具有更多功能,然后使用httplib2并且它非常易于使用http://docs.python-requests.org/
答案 1 :(得分:0)
我已经使用httplib2来完成类似的事情。从httplib2文档中尝试:
import httplib2
import urllib
data = {'name': 'fred', 'address': '123 shady lane'}
body = urllib.urlencode(data)
h = httplib2.Http()
resp, content = h.request("http://example.com", method="POST", body=body)
然后,您应该能够处理第二台django服务器中的 POST ,并将相应的结果返回给第一台django服务器。