运行时错误 - 跳过一行用户输入(扫描仪)

时间:2012-08-24 22:29:35

标签: java java.util.scanner

在我的测试文件中,我试图从用户接收3个输入但是只接收到2个输入,似乎程序正在跳过in.nextLine()代码行。这是我的代码:

import java.util.Scanner;

public class IngredientTester
{
   public static void main(String[] args) {

        Scanner in = new Scanner(System.in);
        /*These 3 inputs work */
        System.out.println("Please enter Ingredient name.");
        String inputName = in.nextLine();
        System.out.println("Please enter Ingredient measurement type.");
        String inputType = in.nextLine();
        System.out.println("Please enter Ingredient amount");
        double inputAmount = in.nextDouble();

        Ingredient inputIngredient = new Ingredient(inputName,inputType,inputAmount);
        System.out.println(inputIngredient.getName() + "- " + inputIngredient.getAmount() + " " + inputIngredient.getMeasurement());

        System.out.println("Please enter Ingredient name.");
        inputName = in.nextLine();
                /* ^ the input above does not work, but the ones below do work */
        System.out.println("Please enter Ingredient measurement type.");
        inputType = in.nextLine();
        System.out.println("Please enter Ingredient amount");
        inputAmount = in.nextDouble();

        inputIngredient.setAmount(inputAmount); 
        inputIngredient.setName(inputName); 
        inputIngredient.setMeasurement(inputType);
        System.out.println(inputIngredient.getName() + "- " + inputIngredient.getAmount() + " " + inputIngredient.getMeasurement());
    }

}

1 个答案:

答案 0 :(得分:1)

问题在于你正在使用:

double inputAmount = in.nextDouble();

不仅会读取您的第一个输入金额,而且会将回车符传递给下一个readLine语句。

解决方案是首先使用回车:

double inputAmount = Double.parseDouble(in.nextLine());