我有array[]
个对象,由于某些原因我无法将其更改为List<>
,是否可以根据1中的值对array[]
个对象进行排序对象的领域?
例如
arrayOfFruit[] fruit;
fruit.sort(name);
答案 0 :(得分:2)
使用Array .. ::。Sort Method(Array,IComparer)
答案 1 :(得分:1)
如果要清楚区分选择器和 comparer ,可以使用此助手类。太糟糕了,你不能使用“类扩展方法”来为Array.Sort
提供一组带选择器的重载。
public static class SelectingComparer<T>
{
public static IComparer<T> Create<U>(Func<T, U> selector)
{
return new SelectingComparerImpl<U>(selector, null);
}
public static IComparer<T> Create<U>(Func<T, U> selector, IComparer<U> comparer)
{
return new SelectingComparerImpl<U>(selector, comparer.Compare);
}
public static IComparer<T> Create<U>(Func<T, U> selector, Comparison<U> comparison)
{
return new SelectingComparerImpl<U>(selector, comparison);
}
private class SelectingComparerImpl<U>
: IComparer<T>
{
private Func<T, U> selector;
private Comparison<U> comparer;
public SelectingComparerImpl(Func<T, U> selector, Comparison<U> comparer)
{
if (selector == null)
throw new ArgumentNullException();
this.selector = selector;
this.comparer = comparer ?? Comparer<U>.Default.Compare;
}
public int Compare(T x, T y)
{
return this.comparer(this.selector(x), this.selector(y));
}
}
}
使用中:
public class Testing
{
public void Foo()
{
FileInfo[] files = new FileInfo[30];
// FILL THE FILE ARRAY
Array.Sort(files, SelectingComparer<FileInfo>.Create(file => file.Name));
Array.Sort(files, SelectingComparer<FileInfo>.Create(file => file.Name, StringComparer.OrdinalIgnoreCase));
}
}
答案 2 :(得分:0)
您可以使用IComparer作为排序参数
答案 3 :(得分:0)
void SomeMethod()
{
Fruit fruits[] = GetArrayOfFruit();
Array.Sort(fruits, FruitNameComparer);
}
int FruitNameComparer(Fruit lhsOfQEquals, Fruit rhsOfEquals)
{
return String.Compare(lhsOfQEquals.Name, rhsOfEquals.Name);
}