mcrypt的:
import java.security.NoSuchAlgorithmException;
import javax.crypto.Cipher;
import javax.crypto.NoSuchPaddingException;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;
public class MCrypt {
private String iv = "fedcba9876543210";
private IvParameterSpec ivspec;
private SecretKeySpec keyspec;
private Cipher cipher;
private String SecretKey = "0123456789abcdef";
public MCrypt()
{
ivspec = new IvParameterSpec(iv.getBytes());
keyspec = new SecretKeySpec(SecretKey.getBytes(), "AES");
try {
cipher = Cipher.getInstance("AES/CBC/NoPadding");
} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (NoSuchPaddingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public byte[] encrypt(String text) throws Exception
{
if(text == null || text.length() == 0)
throw new Exception("Empty string");
byte[] encrypted = null;
try {
cipher.init(Cipher.ENCRYPT_MODE, keyspec, ivspec);
encrypted = cipher.doFinal(padString(text).getBytes());
} catch (Exception e)
{
throw new Exception("[encrypt] " + e.getMessage());
}
return encrypted;
}
public byte[] decrypt(String code) throws Exception
{
if(code == null || code.length() == 0)
throw new Exception("Empty string");
byte[] decrypted = null;
try {
cipher.init(Cipher.DECRYPT_MODE, keyspec, ivspec);
decrypted = cipher.doFinal(hexToBytes(code));
} catch (Exception e)
{
throw new Exception("[decrypt] " + e.getMessage());
}
return decrypted;
}
public static String bytesToHex(byte[] data)
{
if (data==null)
{
return null;
}
int len = data.length;
String str = "";
for (int i=0; i<len; i++) {
if ((data[i]&0xFF)<16)
str = str + "0" + java.lang.Integer.toHexString(data[i]&0xFF);
else
str = str + java.lang.Integer.toHexString(data[i]&0xFF);
}
return str;
}
public static byte[] hexToBytes(String str) {
if (str==null) {
return null;
} else if (str.length() < 2) {
return null;
} else {
int len = str.length() / 2;
byte[] buffer = new byte[len];
for (int i=0; i<len; i++) {
buffer[i] = (byte) Integer.parseInt(str.substring(i*2,i*2+2),16);
}
return buffer;
}
}
private static String padString(String source)
{
char paddingChar = ' ';
int size = 16;
int x = source.length() % size;
int padLength = size - x;
for (int i = 0; i < padLength; i++)
{
source += paddingChar;
}
return source;
}
}
主要
mcrypt = new MCrypt();
/* Encrypt */
String encrypted = MCrypt.bytesToHex( mcrypt.encrypt("Text to Encrypt") );
//Returns 9975e28df055c336a9b7090b03f88689
/* Decrypt */
String decrypted = new String( mcrypt.decrypt( encrypted ) );
//Returns "Text to Encrypt "
问题:
String encrypted = MCrypt.bytesToHex( mcrypt.encrypt("Text to Encrypt") );
加密返回:9975e28df055c336a9b7090b03f88689(不正确)
String decrypted = new String( mcrypt.decrypt( encrypted ) );
解密返回:“要加密的文字”(正确反映加密的内容,加密后有“”)
我把它缩小到这条线:
encrypted = cipher.doFinal(padString(text).getBytes());
我尝试更改padString函数,以便char paddingChar = 0;
代替char paddingChar = ' ';
而没有运气......
正确加密后,“要加密的文字”应变成“cb4b4ca864213684070465b38783a6c8”
答案 0 :(得分:3)
AES是一个块密码。它将一个256位块(= 16字节)加密成另一个256位块。您的明文“要加密的文本”是15个字符,或248位。 AES无法按原样对其进行加密,但必须添加一些填充以使其达到整个块。
如果明确添加填充字符,则必须明确删除它。每个不同的填充字符将对解密产生很大影响。平均而言,改变输入明文块中的一位将改变输出密文块中50%的位。
最简单的解决方案是在Java中使用填充工具中的buit。您将密码指定为:"AES/CBC/NoPadding"
。将此更改为"AES/CBC/PKCS5Padding"
以进行加密和解密。不要担心密文的样子,只要检查明文是否与字符串为decyphered cyphertext匹配。
常见错误是使用getBytes()
将文本字符串转换为字节数组。不要这样做,因为它容易出错。您应该精确指定在字符和字节之间使用的映射。使用类似的东西:
byte[] plainBytes = plaintextString.getBytes("UTF-8");
和另一边相似。不要依赖系统默认值始终相同。