我在主要活动中使用了以下代码
public void button(View v){
//Create an intent to start the new activity.
// Our intention is to start secondActivity
Intent intent = new Intent();
intent.setClass(this,Activity.class);
startActivity(intent);
}
单击按钮时如何显示随机活动?请帮我!
答案 0 :(得分:2)
调试了上面的一些代码,因为setClass()中有一个错误..这个有效:
Random rnd = new Random();
int x=rnd.nextInt(3)+1;
Intent myIntent = new Intent();
switch(x){
case 1:
myIntent.setClass(view.getContext(),Scrn1.class);
break;
case 2:
myIntent.setClass(view.getContext(), Scrn2.class);
break;
case 3:
myIntent.setClass(view.getContext(), Scrn1.class);
break;
}
startActivity(myIntent);
答案 1 :(得分:2)
将所有活动的名称存储在数组中,生成随机数并获取与随机生成的数字相对应的活动。示例代码段
String[] title = new String[] { "Act1.class", "Act2.class","Act1.class","Act4.class","Act5.class"};
public String getRandomActivity(){
Random randomGenerator = new Random();
int randomInt = randomGenerator.nextInt(5);// pass number of elements as parameters
return title[randomInt-1];//this should return class name
}
Intent intent = new Intent(this,getRandomActivity())
startActivity(intent)
答案 2 :(得分:0)
试试这个,假设你有3个活动:
public void button(View v){
Random rnd = new Random();
int x=rnd.nextInt(3)+1;
Intent intent = new Intent();
switch(x){
case 1:
intent.setClass(this,Activity1.class);
break;
case 2:
intent.setClass(this,Activity2.class);
break;
case 3:
intent.setClass(this,Activity3.class);
break;
}
startActivity(intent);
}