代码如下所示:
传感器类:
@Entity
@Table(name = "sensor")
public class Sensor {
@Id
@Column(name = "id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
@ManyToOne
private SensorType sensorType;
@NotEmpty
@Size(min = 3, max = 255)
@Column(name = "name")
private String name;
......
}
SensorType:
@Entity
@Table(name = "sensortype")
public class SensorType {
@Id
@Column(name = "id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
@Column(name = "type")
private String type;
......
}
当我尝试插入新传感器时出现错误,SensorType为null 因为我只是从jsp向SensorController发送SensorType“id” 并且控制器需要一个SensorType对象。
SensorController:
@Controller
public class SensorController {
@Autowired
private ISensor sensorService;
@RequestMapping(value = "/sensor/add", method = RequestMethod.POST)
public String add(Sensor sensor, BindingResult result, Model model) {
if (result.hasErrors()) {
return "sensorAdd";
}
sensorService.insert(sensor);
return "redirect:/sensors";
}
}
我该如何解决这个问题?
答案 0 :(得分:1)
解决此问题的一种典型方法是以这种方式指定转换器:
public class IdToSensorTypeConveter implements Converter<Integer, SensorType>{
...
@Override
public SensorType convert(Integer id) {
return this.sensorTypeDao.findById(id);
}
}
使用Spring注册此转换器:
<bean id="conversionService" class="org.springframework.format.support.FormattingConversionServiceFactoryBean">
<property name="converters">
<set>
<bean class="IdToSensorTypeConveter"/>
</set>
</property>
</bean>
<mvc:annotation-driven conversion-service="conversionService"/>
现在,如果您提交的表单在传感器字段中有一个sensorType字段,它将自动绑定到上述转换器返回的sensorType。