我正在尝试访问android中的soap webservices。
AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL);
...
...
String result = (String) httpTransport.responseDump;
我将响应结果字符串作为xml格式,如下所示,
<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soapenv:Body>
<sampleResponse xmlns="http://impl.test.com">
<sampleReturn>
<clientNameList>
<clientNameList>
<clientID>1</clientID>
</clientNameList>
<clientNameList>
<clientID>2</clientID>
</clientNameList>
</clientNameList>
<message>SUCCESS</message>
</sampleReturn>
</sampleResponse>
</soapenv:Body>
</soapenv:Envelope>
使用Simple XML Serialization(simple-xml-2.6.6.jar)将此xml解析为Pojo。 参考: here
Persister persister = new Persister();
UserResponse userResponse = persister.read(UserResponse.class, result);
现在我得到了例外
Element 'Body' does not have a match in class com.test.UserResponse at line 1
了解更多代码信息here
我该如何解决这个问题?
UserResponse.java(POJO类)
public class UserResponse {
private String message = null;
private Client[] clientNameList = null;
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
public void setClientNameList(Client[] clientNameList) {
this.clientNameList = clientNameList;
}
public Client[] getClientNameList() {
return clientNameList;
}
}
和Client.java
public class Client {
private int clientID;
public void setClientID(int clientID) {
this.clientID = clientID;
}
public int getClientID() {
return clientID;
}
}
答案 0 :(得分:0)
您的回复中存在问题。您将一个接一个地获得<clientNameList>
两次,这可能会导致您在解析XML时遇到问题。因此,最好相应地更改您的回复。