如何获得PropertyGrid的单元格值(c#)?

时间:2012-08-23 12:15:15

标签: c# propertygrid

如何在c#中获取属性网格项和项的值? 例如:

Name : Ali
LastName : Ahmadi

(Name和LastName是propertygrid的2个属性)

2 个答案:

答案 0 :(得分:5)

PropertyGrid只是对象的组件模型表示的视图。我会说:而不是看网格,看看组件模型,例如:

var props = TypeDescriptor.GetProperties(obj);
foreach(var prop in props) {
    string name = prop.DisplayName;
    if(string.IsNullOrEmpty(name)) name = prop.Name;
    Console.WriteLine("{0}: {1}", name, prop.GetValue(obj));
}

答案 1 :(得分:3)

正确答案是:

private void button1_Click(object sender, EventArgs e)
{
    GridItem gi = propertyGrid1.SelectedGridItem;
    while (gi.Parent != null)
    {
        gi = gi.Parent;
    }
    foreach (GridItem item in gi.GridItems)
    {
        ParseGridItems(item); //recursive
    }
}

private void ParseGridItems(GridItem gi)
{
    if (gi.GridItemType == GridItemType.Category)
    {
        foreach (GridItem item in gi.GridItems)
        {
            ParseGridItems(item);
        }
    }
    textBox1.Text += "Lable : "+gi.Label + "\r\n";
    if(gi.Value != null)
        textBox1.Text += "Value : " + gi.Value.ToString() + "\r\n";
}