Question

我从Flickr得到了正确答案：

<?xml version="1.0" encoding="utf-8" ?>
<rsp stat="ok">
  <photoset id="72157630469695108" owner="15823425@N00" primary="5110549866" secret="fd716fb5ee" server="1136" farm="2" photos="101" count_views="67" count_comments="0" count_photos="101" count_videos="0" can_comment="0" date_create="1341701808" date_update="1345054078">
    <title>Montana</title>
    <description />
  </photoset>
</rsp>

出于某种原因，我无法获得头衔，我已经尝试了以下内容：

$album_info = simplexml_load_file($album_info_xml); // this is what the response is stored in

echo $album_info['photoset']['title'];

foreach($album_info->photoset as $ps) {
    echo $ps['title'];
}

还有其他一些疯狂的事情，我知道这是一件愚蠢的事情但不知道我错过了什么。

可以在此处看到响应：http://www.flickr.com/services/api/explore/flickr.photosets.getInfo

只需使用72157630469695108作为设置ID，或者使用此网址：http://api.flickr.com/services/rest/?method=flickr.photosets.getInfo&api_key=7ccedd2c89ca10303394b8085541d9de&photoset_id=72157630469695108

Answer 1

您应该直接使用SimpleXMLElement，然后使用xpath来查找您的节点。

$album_info = new SimpleXMLElement('<?xml version="1.0" encoding="utf-8" ?>
<rsp stat="ok">
  <photoset id="72157630469695108" owner="15823425@N00" primary="5110549866" secret="fd716fb5ee" server="1136" farm="2" photos="101" count_views="67" count_comments="0" count_photos="101" count_videos="0" can_comment="1" date_create="1341701808" date_update="1345054078">
    <title>Montana</title>
    <description />
  </photoset>
</rsp>'); // this is what the response is stored in

$result = $album_info->xpath('//title');

foreach ($result as $title)
{
  echo $title . "\n";
}

Working example

Answer 2

对于处于相同位置的任何人来说，这就是诀窍

$albumName = $album_info->photoset->title;

PHP Flickr API - 从flickr.photosets.getInfo响应中检索标题

2 个答案: