Question

我的情况是这样的：

<?php
$var1 = "Top of British";
$var2 = "Welcome to British, the TOP country in the world";

$var1 = strtolower($var1);
$var2 = strtolower($var2);

if (strpos($var1, $var2) !== FALSE) {
echo "TRUE";
}
?>

它无法正常工作，我如何检测TOP或英文两种字符串都存在？

Answer 1

从字符串中删除标点符号，将它们都转换为小写，将空格字符上的每个字符串分解为字符串数组，然后遍历每个字符串以查找匹配的单词：

$var1 = preg_replace('/[.,]/', '', "Top of British");
$var2 = preg_replace('/[.,]/', '', "Welcome to British, the TOP country in the world");


$words1 = explode(" ",strtolower($var1));
$words2 = explode(" ",strtolower($var2));

foreach ($words1 as $word1) {
    foreach ($words2 as $word2) {
       if ($word1 == $word2) {
          echo $word1."\n";
          break;
       }
    }
}

DEMO：http://codepad.org/YtDlcQRA

Answer 2

在字符串中找到TOP或BRITISH

<?php
$var1 = "Top of British";
$var2 = "Welcome to British, the TOP country in the world";

$var1 = strtolower($var1);
$var2 = strtolower($var2);

if (strpos($var1, 'top') && strpos($var1, 'british')) {
echo "Either the word TOP or the word BRITISH was found in string 1";
}
?>

更一般地将字符串2中的单词与字符串1中的单词匹配

<?php
$var1 = explode(' ', strtolower("Top of British"));
$var2 = "Welcome to British, the TOP country in the world";

$var2 = strtolower($var2);

foreach($var1 as $needle) if (strpos($var2, $needle)) echo "At least one word in str1 was found in str 2";

?>

Answer 3

检查短语中单词交集的通用示例您可以在结果中查看任何过时的停用词，例如“of”或“to”

<?php
$var1 = "Top of British";
$var2 = "Welcome to British, the TOP country in the world";

$words1 = explode(' ', strtolower($var1));
$words2 = explode(' ', strtolower($var2));

$iWords = array_intersect($words1, $words2);

if(in_array('british', $iWords ) && in_array('top', $iWords))
  echo "true";

Answer 4

PHP具有查找属于两个数组的元素的函数：

$var1 = explode(" ", strtolower("Top of British"));
$var2 = explode(" ", strtolower("Welcome to British, the TOP country in the world"));
var_dump(array_intersect($var1, $var2)); // array(1) { [0]=> string(3) "top" }

PHP：如何比较2字符串中存在的任何一个单词

4 个答案: