我使用Codeigniter,它有timespan()函数,返回时间为1 Year, 10 Months, 2 Weeks, 5 Days, 10 Hours, 16 Minutes
。
我想做的只是显示在x小时前格式化的时间,如果时间在过去24小时内,否则只显示正常的日期时间。
我觉得必须有一个已经完成的功能,但我找不到任何运气。
这是Codeigniter附带的时间跨度函数,我该如何改变呢?
/**
* Timespan
*
* Returns a span of seconds in this format:
* 10 days 14 hours 36 minutes 47 seconds
*
* @access public
* @param integer a number of seconds
* @param integer Unix timestamp
* @return integer
*/
if ( ! function_exists('timespan'))
{
function timespan($seconds = 1, $time = '')
{
$CI =& get_instance();
$CI->lang->load('date');
if ( ! is_numeric($seconds))
{
$seconds = 1;
}
if ( ! is_numeric($time))
{
$time = time();
}
if ($time <= $seconds)
{
$seconds = 1;
}
else
{
$seconds = $time - $seconds;
}
$str = '';
$years = floor($seconds / 31536000);
if ($years > 0)
{
$str .= $years.' '.$CI->lang->line((($years > 1) ? 'date_years' : 'date_year')).', ';
}
$seconds -= $years * 31536000;
$months = floor($seconds / 2628000);
if ($years > 0 OR $months > 0)
{
if ($months > 0)
{
$str .= $months.' '.$CI->lang->line((($months > 1) ? 'date_months' : 'date_month')).', ';
}
$seconds -= $months * 2628000;
}
$weeks = floor($seconds / 604800);
if ($years > 0 OR $months > 0 OR $weeks > 0)
{
if ($weeks > 0)
{
$str .= $weeks.' '.$CI->lang->line((($weeks > 1) ? 'date_weeks' : 'date_week')).', ';
}
$seconds -= $weeks * 604800;
}
$days = floor($seconds / 86400);
if ($months > 0 OR $weeks > 0 OR $days > 0)
{
if ($days > 0)
{
$str .= $days.' '.$CI->lang->line((($days > 1) ? 'date_days' : 'date_day')).', ';
}
$seconds -= $days * 86400;
}
$hours = floor($seconds / 3600);
if ($days > 0 OR $hours > 0)
{
if ($hours > 0)
{
$str .= $hours.' '.$CI->lang->line((($hours > 1) ? 'date_hours' : 'date_hour')).', ';
}
$seconds -= $hours * 3600;
}
$minutes = floor($seconds / 60);
if ($days > 0 OR $hours > 0 OR $minutes > 0)
{
if ($minutes > 0)
{
$str .= $minutes.' '.$CI->lang->line((($minutes > 1) ? 'date_minutes' : 'date_minute')).', ';
}
$seconds -= $minutes * 60;
}
if ($str == '')
{
$str .= $seconds.' '.$CI->lang->line((($seconds > 1) ? 'date_seconds' : 'date_second')).', ';
}
return substr(trim($str), 0, -1);
}
}
答案 0 :(得分:2)
if( time() - $yourTime <= 86400 ) { // 86400 seconds in a day
echo timespan($yourTime);
} else {
echo date('m/d/Y \a\t H:i:s', $yourTime);
}
不要依赖任何框架,特别是坏框架!
答案 1 :(得分:2)
此函数将接受字符串,数字(unix)时间戳或DateTime
对象。它还接受jQuery.now()
。时间可能是未来或过去。
function time_ago($time=false, $just_now=false) {
if ($time instanceOf DateTime)
$time = $time->getTimestamp();
elseif (is_numeric($time))
$time = date('m/d/y h:i A', $time);
if (strtotime($time) === false)
$time = date('m/d/y h:i A', time());
$interval = date_create($time)->diff(date_create('now'));
$adjective = strtotime($time) > time() ? 'from now' : 'ago';
return (
$interval->days > 0 ?
$time : (
$interval->h < 1 && $interval->i < 1 && $just_now ?
'just now' :
(
$interval->h > 1 ?
$interval->h.' hour'.(
$interval->h > 1 ?
's' :
''
).' ago' :
$interval->i.' minutes'.' '.$adjective
)
)
);
}
echo time_ago('8/22/2012 5:00 PM'); // 3 hours ago
echo time_ago('8/21/2012 5:00 PM'); // 8/21/2012 5:00 PM
echo time_ago(time()); // 0 hours ago
echo time_ago(time(), true); // just now
echo time_ago(strtotime('5 days ago')); // 08/17/12 08:18 PM
echo time_ago(strtotime('5 hours ago')); // 5 hours ago
echo time_ago(strtotime('5 minutes ago')); // 5 minutes ago
echo time_ago(strtotime('+5 minutes')); // 5 minutes from now
echo time_ago('jQuery.now()', true); // just now
echo time_ago('sweet explosions, bro!', true); // just now
<强>文档强>
date
- http://php.net/manual/en/function.date.php DateTime
object - http://www.php.net/manual/en/book.datetime.php DateInterval
object - http://www.php.net/manual/en/class.dateinterval.php is_numeric
- http://php.net/manual/en/function.is-numeric.php 答案 2 :(得分:1)
提供$格式以满足您的需求。几乎可以接受任何输入。
<?php
/**
* RelativeTime - pretty printed
* @author Dejan Marjanovic
*/
class Site5_RelativeTime
{
private $interval = '';
public function __construct()
{
call_user_func_array(array($this, 'calculate'), func_get_args());
}
public function calculate($start, $end = NULL)
{
if ( empty($start))
return false;
if (empty($end))
$end = time();
if ( ! is_numeric($start))
$start = strtotime($start);
if ( ! is_numeric($end))
$end = strtotime($end);
if($start > $end)
$future = TRUE;
$start = '@' . $start;
$end = '@' . $end;
if ( ! ($start instanceof DateTime))
$start = new DateTime($start);
if ($end === null)
$end = new DateTime();
if ( ! ($end instanceof DateTime))
$end = new DateTime($end);
$interval = $end->diff($start);
$get_plural = function($int, $str)
{
return $int > 1? $str.'s': $str;
};
$format = array();
if ($interval->y !== 0)
$format[] = "%y " . $get_plural($interval->y, "year");
if ($interval->m !== 0)
$format[] = "%m " . $get_plural($interval->m, "month");
if ($interval->d !== 0)
$format[] = "%d " . $get_plural($interval->d, "day");
if ($interval->h !== 0)
$format[] = "%h " . $get_plural($interval->h, "hour");
if ($interval->i !== 0)
$format[] = "%i " . $get_plural($interval->i, "minute");
if ($interval->s !== 0)
{
if ( ! count($format))
{
$this->interval = "less than a minute";
return;
}
else
{
$format[] = "%s " . $get_plural($interval->s, "second");
}
}
if (count($format) > 1)
{
$format = array_shift($format) . " and " . array_shift($format);
}
else
{
$format = array_pop($format);
}
$tense = ($future === TRUE)? 'from now': 'ago';
$this->interval = $interval->format($format) . ' ' . $tense;
}
public function __toString()
{
return $this->interval;
}
}