Question

是的，我得到了这个工作，但由于某种原因我的循环仍然显示错误的值......

$db = JFactory::getDBO();
    $query = "select * from jos_gerencia_vendas AS a LEFT JOIN jos_gerencia_clientes AS b ON b.Id=a.id_cliente where a.id_edicao = ".$iddaedicao." order by b.nomecliente ASC";

    $db->setQuery($query);
    $list = $db->loadObjectList();
    foreach ($list as $item)
            {
            $Id = $item->Id;
            $id_venda = $item->id_venda;
            $id_edicao = $item->id_edicao;
            $id_vendedor = $item->id_vendedor;
            $id_cliente = $item->id_cliente;
            $id_produto = $item->id_produto;
            $data_insercao = $item->data_insercao;
            $pagina = $item->pagina;

我需要从foreach循环中的jos_gerencia_vendas中检索$ Id变量，任何线索？

Answer 1

如果两个表上都有一个名为Id的列，那么当你获得$ item-＆gt;时，Id将是不明确的。你可以在mysql控制台或phpmyadmin上运行查询，看它是否抛出任何错误吗？

Answer 2

您可以使用别名从查询中检索信息，如

$query = "select a.id as id,a.col1 as id_venda,a.col2 as id_edicao,b.col1 as id_vendedor from jos_gerencia_vendas AS a LEFT JOIN jos_gerencia_clientes AS b ON b.Id=a.id_cliente where a.id_edicao = ".$iddaedicao." order by b.nomecliente ASC";

    $db->setQuery($query);
    $list = $db->loadObjectList();
    foreach ($list as $item)
            {
            $Id = $item->Id;
            $id_venda = $item->id_venda;
            $id_edicao = $item->id_edicao;
            $id_vendedor = $item->id_vendedor;

我的joomla问题离开了加入mysql

2 个答案: