Question

select 
    id, amount - (select sum(amount) as amount 
                  from table2 
                  where column = 'value' and table1.id = table2.id 
                  group by table2.id) as amount
from 
    table1 
order by 
    table1.id

结果是来自table1的所有值 - 来自amount的{{1}}除了table2以外的table1.id，它们都是空值。

所以这一切都很好，除了我有空值，因为我需要这些值为table2.id值

也试过这样的东西，但仍然无法正常工作

table1.amount

然后我得到select id, amount - isnull((select sum(amount) as amount from table2 where column = 'value' and table1.id = table2.id group by table2.id), table1.amount) as amount from table1 order by table1.id，但结果集中为空的0.00确实在table1.id

中有实际金额值

我需要的概述

table1.amount

所以我需要table1 - 表2中的值来获取结果表

Answer 1

更好地做到这一点

select
t1.id, t1.amount - isnull(t2.amountTable2,0) as 'amount'
from table1 T1
left join (select id, sum(ammunt) as 'amountTable2' from table2 group by Id) T2
       on t1.id = t2.id
order by t1.id

这将获得Sum中每个ID的总table2 那么join将通过id，并发挥作用。如果table2中没有ID，则使用0

那个答案考虑（我最初认为那个）t2.Id可以重复如果它是唯一的，请按

删除该组

select
    t1.id, t1.amount - isnull(t2.amount,0) as 'Totalamount'
    from table1 T1
    left join table2 T2
           on t1.id = t2.id
    order by t1.id

SQL Server查询获取行表1 - 行表2没有空值

1 个答案: