Question

我有一个客户提供的以下XML，我需要从中提取以下项目：

<CustomerProductName>
<ProductName>
<ProductAssetName>

将每个<CustomerProducts>部分视为单独的订单。

我可以访问<CustomerProducts>并提取<CustomerProductName>而没有任何问题，并迭代每个部分中的值。

但我无法看到我如何得到它下面的值。如果有人可以给我一些关于如何实现这一点的指示，我会感激，因为我现在已经尝试了一天。

基本代码位于XML

之下

<?xml version="1.0"?>
<Products_Root>
    <Products_IPN VendorID="11344" >
        <CustomerProducts CustomerProductName="Test" ProductCount="7">
            <Products ProductType="BOOK" ProductName="Donald" >
                <ProductComponents ProductAssetName="Donald.pdf" />
                <ProductSpecs SpecClass="MEASUREMENT" SpecType="MARGINS" SpecValue="PER FILE"/>
                <ProductSpecs SpecClass="OPERATION" SpecType="BIND" SpecValue="SADDLE"/>
            </Products>
            <Products ProductType="BOOK" ProductName="Duck">
                <ProductComponents ProductAssetName="Duck.pdf"/>
                <ProductSpecs SpecClass="MEASUREMENT" SpecType="MARGINS" SpecValue="PER FILE"/>
                </Products>
        </CustomerProducts>
        <CustomerProducts CustomerProductName="Test2" ProductCount="2">
            <Products ProductType="BOOK" ProductName="Micky">
                <ProductComponents ProductAssetName="Mouse.pdf" />
                <ProductComponents ProductAssetName="Mouse.pdf" />
                <ProductSpecs SpecClass="MEASUREMENT" SpecType="MARGINS" SpecValue="PER FILE"/>
            </Products>
            <CustomerProductSpecs SpecClass="OPERATION" SpecType="KITTING" SpecValue="SHRINKWRAP KIT"/>
        </CustomerProducts>
        <CustomerProducts CustomerProductName="Test3" ProductCount="6">
            <Products ProductType="BOOK" ProductName="Minnie">
                <ProductComponents ProductAssetName="Mouse" />
                <ProductSpecs SpecClass="MEASUREMENT" SpecType="MARGINS" SpecValue="PER FILE"/>
            </Products>
        </CustomerProducts>
    </Products_IPN>
</Products_Root>

到目前为止我的VBScript代码

Dim xmlDoc, objNodeList, plot

Set xmlDoc = CreateObject("Msxml2.DOMDocument")
xmlDoc.setProperty "SelectionLanguage", "XPath"
xmlDoc.load("E:\dropbox\Dropbox\Hobbs\Xerox Example Files\test.xml")

Set objNodeList = xmlDoc.getElementsByTagName("CustomerProducts")

plot="No Value"
If objNodeList.length > 0 then
    For each x in objNodeList
        JobName=x.getattribute("CustomerProductName")
        msgbox JobName
    Next
Else
    msgbox chr(34) & "CustomerProducts" & chr(34) & " field not found."
End If

Answer 1

您已经将选择语言设置为XPath，也许您应该使用它。：）

Dim xmlDoc, CustomerProducts, Products
Dim plot, CustomerProductName, ProductName

Set xmlDoc = CreateObject("Msxml2.DOMDocument")
xmlDoc.setProperty "SelectionLanguage", "XPath"
xmlDoc.load("E:\dropbox\Dropbox\Hobbs\Xerox Example Files\test.xml")

plot="No Value"

For Each CustomerProducts In xmlDoc.SelectNodes("//CustomerProducts")
  CustomerProductName = CustomerProducts.getAttribute("CustomerProductName")

  For Each Products In CustomerProducts.SelectNodes("./Products")
    ProductName = Products.getAttribute("ProductName")

    MsgBox CustomerProductName & " - " & ProductName
  Next
Next

VBScript迭代XML子节点并检索值

1 个答案: