Question

我有这些xml数据集

<Address>
<Rowinfo>
<LocatorDesignator>Dwelling  (Part Of), Null</LocatorDesignator>
<LocatorName>Flat  - Buena Villa House</LocatorName>
<thoroughfare>James Passage</thoroughfare>
<AddressArea>Modakeke island</AddressArea>
</Rowinfo>
<Rowinfo>
<LocatorDesignator>Flat  - Buena Villa House, 1</LocatorDesignator>
<LocatorName>Flat  3a  Anderson's House</LocatorName>
<thoroughfare>Abesinia Passage</thoroughfare>
<AddressArea> Buena Villa Road</AddressArea>
</Rowinfo>
<Rowinfo>
<LocatorDesignator>Offices Unit 2a Funlife Building, 02a</LocatorDesignator>
<LocatorName>Offices Unit 2a   Funlife Building  <LocatorName>
<thoroughfare> Modakeke island</thoroughfare>
<AddressArea>Laguna Estate</AddressArea>
</Rowinfo>
</Address>

我想将他们变成这个

<LocatorDesignator>Dwelling(Part Of)</LocatorDesignator>
<LocatorName>Buena Villa House</LocatorName>
<thoroughfare>James Passage </thoroughfare>
<AddressArea>Modakeke island</AddressArea>


<LocatorDesignator>Flat 1</LocatorDesignator>
<LocatorName> Anderson's House</LocatorName>
<thoroughfare>Abesinia Passage</thoroughfare>
<AddressArea> </AddressArea>


<LocatorDesignator>Offices Unit 2a</LocatorDesignator>
<LocatorName> Funlife Building  <LocatorName>
<thoroughfare> </thoroughfare>
<AddressArea>Laguna Estate</AddressArea>

基本上在（addressarea）元素中我想用estate和island作为后缀提取值。在通道元素中，我想删除带有estate和island作为后缀的值。房屋或建筑物的任何值都将在定位器名称中提取。

Answer 1

<强>予。删除AddressArea中未以"island"结尾的文本节点：

<xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>

     <xsl:template match="node()|@*">
         <xsl:copy>
           <xsl:apply-templates select="node()|@*"/>
         </xsl:copy>
     </xsl:template>

     <xsl:template match=
     "AddressArea/text()
       [substring(., string-length() -5) != 'island'
       and
        substring(., string-length() -5) != 'Estate'
       ]"/>
</xsl:stylesheet>

将此转换应用于提供的XML文档（更正为格式正确）：

<Address>
    <Rowinfo>
        <LocatorDesignator>Dwelling  (Part Of), Null</LocatorDesignator>
        <LocatorName>Flat  - Buena Villa House</LocatorName>
        <thoroughfare>James Passage</thoroughfare>
        <AddressArea>Modakeke island</AddressArea>
    </Rowinfo>
    <Rowinfo>
        <LocatorDesignator>Flat  - Buena Villa House, 1</LocatorDesignator>
        <LocatorName>Flat  3a  Anderson's House</LocatorName>
        <thoroughfare>Abesinia Passage</thoroughfare>
        <AddressArea></AddressArea>
    </Rowinfo>
    <Rowinfo>
        <LocatorDesignator>Offices Unit 2a Funlife Building, 02a</LocatorDesignator>
        <LocatorName>Offices Unit 2a   Funlife Building  </LocatorName>
        <thoroughfare> Modakeke island</thoroughfare>
        <AddressArea>Laguna Estate</AddressArea>
    </Rowinfo>
</Address>

<强> II。处理thoroughfare

只需将此模板添加到上面的代码中：

 <xsl:template match=
  "thoroughfare/text()
       [substring(., string-length() -5) = 'island']"/>

现在完整的代码：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>

     <xsl:template match="node()|@*">
         <xsl:copy>
           <xsl:apply-templates select="node()|@*"/>
         </xsl:copy>
     </xsl:template>

     <xsl:template match=
     "AddressArea/text()
       [substring(., string-length() -5) != 'island'
       and
        substring(., string-length() -5) != 'Estate'
       ]"/>

     <xsl:template match=
     "thoroughfare/text()
       [substring(., string-length() -5) = 'island']"/>
</xsl:stylesheet>

，当应用于提供的XML文档（上图）时，会生成所需的正确结果：

<Address>
    <Rowinfo>
        <LocatorDesignator>Dwelling  (Part Of), Null</LocatorDesignator>
        <LocatorName>Flat  - Buena Villa House</LocatorName>
        <thoroughfare>James Passage</thoroughfare>
        <AddressArea>Modakeke island</AddressArea>
    </Rowinfo>
    <Rowinfo>
        <LocatorDesignator>Flat  - Buena Villa House, 1</LocatorDesignator>
        <LocatorName>Flat  3a  Anderson's House</LocatorName>
        <thoroughfare>Abesinia Passage</thoroughfare>
        <AddressArea/>
    </Rowinfo>
    <Rowinfo>
        <LocatorDesignator>Offices Unit 2a Funlife Building, 02a</LocatorDesignator>
        <LocatorName>Offices Unit 2a   Funlife Building  </LocatorName>
        <thoroughfare/>
        <AddressArea>Laguna Estate</AddressArea>
    </Rowinfo>
</Address>

<强> III。 XSLT 2.0解决方案

这更容易 - 只需在谓词（XSLT 1.0解决方案）中使用标准XPath 2.0函数 ends-with() 。

使用xslt删除和提取文本节点中的字符串值

1 个答案: