我创建了一个强类型视图。我想将IEnumerable Object或数据从View传递给Controller。以下是我的模型,控制器,查看
我的型号:
public class UserDetailsClass
{
public static FeedbackDatabaseDataContext context = new FeedbackDatabaseDataContext();
public class Tablefields
{
[Key]
public int ID { get; set; }
[Required(ErrorMessage = "Email is required")]
public string EmailID { get; set; }
[Required(ErrorMessage="Password is required")]
public string Password { get; set; }
[Required(ErrorMessage = "First Name is required")]
public string FirstName { get; set; }
[Required(ErrorMessage = "Last Name is required")]
public string LastName { get; set; }
}
public static List<UserDetails> getalluser()
{
var lst = (from r in context.UserDetails select r);
return lst.ToList();
}
}
我的控制器
public ActionResult Test()
{
IList<UserDetailsClass.Tablefields> viewmodel = new List<UserDetailsClass.Tablefields>();
var q = UserDetailsClass.getalluser().ToList();
foreach (SQLOperation.Models.UserDetails item in q)
{
UserDetailsClass.Tablefields viewItem = new UserDetailsClass.Tablefields();
viewItem.EmailID = item.Email;
viewItem.FirstName = item.FirstName;
viewItem.LastName = item.LastName;
viewItem.Password = item.Password;
viewmodel.Add(viewItem);
}
return View(viewmodel);
}
[HttpPost]
public ActionResult Test(IEnumerable<UserDetailsClass.Tablefields> items)
{
return View();
}
我的查看:
@model IEnumerable<SQLOperation.Models.UserDetailsClass.Tablefields>
@{
ViewBag.Title = "Test";
}
<h2>Test</h2>
@using (Html.BeginForm())
{
<table>
<tr>
<th>
EmailID
</th>
<th>
Password
</th>
<th>
FirstName
</th>
<th>
LastName
</th>
<th></th>
</tr>
@foreach (var item in Model)
{
<tr>
<td>
@Html.DisplayFor(modelItem => item.EmailID)
</td>
<td>
@Html.DisplayFor(modelItem => item.Password)
</td>
<td>
@Html.DisplayFor(modelItem => item.FirstName)
</td>
<td>
@Html.DisplayFor(modelItem => item.LastName)
</td>
</tr>
}
</table>
<input type="submit" value="submit" />
}
我在项中没有任何价值。当我在其上设置断点时,它在项中显示 NULL 我完全对如何将值传递给控制器感到困惑。
谢谢你, Amol
答案 0 :(得分:2)
而不是@Html.DisplayFor
使用@Html.EditorFor
,这样就会在您的表单中进行数据绑定。
此外,由于您正在使用集合,因此需要迭代字段(简化示例):
@for (int row = 0; row < Model.Count; row++)
{
@Html.EditorFor(x => x[row].FirstName )
}
答案 1 :(得分:0)
@for (int i = 0; i < Model.length; i ++)
{
<tr>
<td>
@Html.DisplayFor(model => Model[i].EmailID)
</td>
<td>
@Html.DisplayFor(model => Model[i].Password)
</td>
<td>
@Html.DisplayFor(model => Model[i].FirstName)
</td>
<td>
@Html.DisplayFor(model => Model[i].LastName)
</td>
</tr>
}
</table>
<input type="submit" value="submit" />
}