我的一个活动中有两个表行。第一行将始终包含2个textview,第二行可能包含一个或两个textview(它取决于userinput)。每当我在第二行中有一个textview时,我试图将它跨越到两列。我正在尝试这个
TableRow.LayoutParams param = (LayoutParams)editText.getLayoutParams();
param.span = 2;
txtView.setLayoutParams(param);
但它不起作用。会发生什么,第一行中的第二个txtview被推出屏幕。那么这里的任何人都可以告诉我哪里犯了错误吗?
答案 0 :(得分:5)
我做了这个例子,希望它可以帮助你。
TableLayout table = (TableLayout)findViewById(R.id.table_id_in_xml);
TableRow row = new TableRow(this);
TableRow row2 = new TableRow(this);
TextView col1, col2, col3;
row.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT,LayoutParams.WRAP_CONTENT));
row2.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT,LayoutParams.WRAP_CONTENT));
col1 = new TextView(this);
col2 = new TextView(this);
col3 = new TextView(this);
col1.setText("col1");
col2.setText("col2");
col3.setText("col3");
row.addView(col1);
row.addView(col2);
row.addView(col3);
table.addView(row, new TableLayout.LayoutParams( LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
//HERE IS WHAT YOU NEED
TableRow.LayoutParams params = (TableRow.LayoutParams) row2.getLayoutParams();
params.span = 3; //amount of columns you will span
col1 = new TextView(this);
col1.setText("span on col1 makes it bigger than the others");
col1.setLayoutParams(params);
row2.addView(col1);
table.addView(row2, new TableLayout.LayoutParams( LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));