Question

我们假设你有下表（这里感兴趣的列是cid）：

+-----+-------+-------+-------+---------------------+--------------+
| cid | pid   | rid   | clink | time                | snippet      |
+-----+-------+-------+-------+---------------------+--------------+
| 155 | 11222 |  1499 |  1137 | 2012-08-22 03:05:06 | hi           |
| 138 | 11222 |   241 |  1136 | 2012-08-21 05:25:00 | again        |
| 138 | 11222 |   241 |  1135 | 2012-08-21 05:16:40 | hi           |
| 155 | 11222 |  1499 |  1134 | 2012-08-21 05:11:00 | hi cute      |
| 140 | 11222 | 11223 |  1133 | 2012-08-21 05:05:18 | hi           |
| 154 | 11222 |   565 |  1132 | 2012-08-21 05:04:47 | 7            |
| 153 | 11222 |   272 |  1131 | 2012-08-21 05:04:41 | 6            |
| 146 | 11222 |   362 |  1130 | 2012-08-21 05:04:33 | 5            |
| 152 | 11222 |   364 |  1129 | 2012-08-21 05:04:27 | 4            |
| 151 | 11222 |   390 |  1128 | 2012-08-21 05:04:22 | 3            |
| 150 | 11222 |   333 |  1127 | 2012-08-21 05:04:16 | 2            |
| 148 | 11222 |   268 |  1126 | 2012-08-21 05:04:10 | 1            |
| 140 | 11222 | 11223 |  1125 | 2012-08-21 04:59:57 | hi sir       |
| 147 | 11222 |   283 |  1123 | 2012-08-21 03:29:55 | yo           |
| 140 | 11222 | 11223 |  1121 | 2012-08-21 02:12:13 | hello!       |
| 139 | 11222 |   249 |  1120 | 2012-08-21 02:11:53 | hi :)        |
| 140 | 11222 | 11223 |  1119 | 2012-08-21 02:11:26 | hi :)        |
| 140 | 11222 | 11223 |  1118 | 2012-08-21 02:11:08 | hi too       |
| 139 | 11222 |   249 |  1117 | 2012-08-21 02:11:00 | :P           |
| 139 | 11222 |   249 |  1116 | 2012-08-21 02:10:57 | hi           |
| 139 | 11222 |   249 |  1115 | 2012-08-21 02:10:51 | helo         |
| 139 | 11222 |   249 |  1114 | 2012-08-21 02:06:19 | hi           |
| 139 | 11222 |   249 |  1113 | 2012-08-21 02:05:45 | hi baby      |
| 139 | 11222 |   249 |  1112 | 2012-08-21 02:05:00 | hi           |
| 139 | 11222 |   249 |  1111 | 2012-08-21 02:04:41 | hi           |
| 140 | 11222 | 11223 |  1110 | 2012-08-21 02:04:26 | hi           |
| 140 | 11222 | 11223 |  1108 | 2012-08-21 01:47:40 | hey :)       |
| 139 | 11222 |   249 |  1107 | 2012-08-21 01:44:43 | hi           |
| 138 | 11222 |   241 |  1106 | 2012-08-21 01:44:11 | hi           |
| 138 | 11222 |   241 |  1105 | 2012-08-21 01:09:20 | conv 1 msg 1 |
+-----+-------+-------+-------+---------------------+--------------+

如何仅提取每个cid的第一个匹配项？结果表将是：

+-----+-------+-------+-------+---------------------+--------------+
| cid | pid   | rid   | clink | time                | snippet      |
+-----+-------+-------+-------+---------------------+--------------+
| 155 | 11222 |  1499 |  1137 | 2012-08-22 03:05:06 | hi           |
| 138 | 11222 |   241 |  1136 | 2012-08-21 05:25:00 | again        |
| 140 | 11222 | 11223 |  1133 | 2012-08-21 05:05:18 | hi           |
| 154 | 11222 |   565 |  1132 | 2012-08-21 05:04:47 | 7            |
| 153 | 11222 |   272 |  1131 | 2012-08-21 05:04:41 | 6            |
| 146 | 11222 |   362 |  1130 | 2012-08-21 05:04:33 | 5            |
| 152 | 11222 |   364 |  1129 | 2012-08-21 05:04:27 | 4            |
| 151 | 11222 |   390 |  1128 | 2012-08-21 05:04:22 | 3            |
| 150 | 11222 |   333 |  1127 | 2012-08-21 05:04:16 | 2            |
| 148 | 11222 |   268 |  1126 | 2012-08-21 05:04:10 | 1            |
| 147 | 11222 |   283 |  1123 | 2012-08-21 03:29:55 | yo           |
| 140 | 11222 | 11223 |  1121 | 2012-08-21 02:12:13 | hello!       |
| 139 | 11222 |   249 |  1120 | 2012-08-21 02:11:53 | hi :)        |
+-----+-------+-------+-------+---------------------+--------------+

Answer 1

mysql对此有“欺骗”：

select *
from mytable
group by cid;

这就是你所需要的，因为在mysql中它允许你不聚合非分组列（其他数据库会引发语法错误），在这种情况下它只输出第一次出现每个分组的值。请注意，这不能保证确定“第一次”出现的方式（它将是如何读入行的）

如果您希望首次出现特定，请先排序，然后应用分组作弊：

select *
from (
    -- order by the "time" column descending to get the "most recent" row
    select * from mytable order by time desc
    ) x
group by cid

Answer 2

试试这个，

SELECT *
FROM tableName a 
        INNER JOIN
        (
        SELECT cid, MIN(`time`) MinTime
        FROM tableName
        GROUP BY cid
        ) b ON a.CID = B.cid AND
            a.time = b.MinTime

Answer 3

您可以使用过滤联接：

select  *
from    (
        select  cid
        ,       min(time) as min_time
        from    YourTable
        group by
                cid
        ) filter
join    YourTable yt
on      filter.cid = yt.cid
        and filter.min_time = yt.time

Answer 4

我知道它是一个旧线程，接受的解决方案只能找回有多个出现的列。这对我有用：

SELECT cid,pid,rid,clink,max(time),snippet FROM mytable GROUP BY cid

Answer 5

在MySQL 8中，您将为此使用window functions

SELECT cid, pid, rid, clink, time, snippet
FROM (
  SELECT t.*, ROW_NUMBER() OVER (PARTITION BY cid ORDER BY time) rn
  FROM t
) t
WHERE rn = 1

MySQL在每个唯一值的第一次出现时选择行

5 个答案: