从完整网址中提取第一个网址细分

Question

如何从完整网址中提取第一个网址段？应清理第一个网址细分，将-替换为空格。

完整网址

http://www.domain.com/River-Island/River-Island-T-Shirt-with-Triangle-Girl-Print/Prod/pgeproduct.aspx?iid=2516020

渴望的超越

River Island

Answer 1

您可以使用：

$url = 'http://www.domain.com/River-Island/River-Island-T-Shirt-with-Triangle-Girl-Print/Prod/pgeproduct.aspx?iid=2516020';
$parsed = parse_url($url);
$path = $parsed['path'];
$path_parts = explode('/', $path);
$desired_output = $path_parts[1]; // 1, because the string begins with slash (/)

Answer 2

$page = explode('/', substr($_SERVER['REQUEST_URI'], 1), 2);
echo str_replace("-"," ", $page[0]);

Answer 3

试试这个：/http:\/\/[^\/]+\/([^\/]+)/i

见这里：http://regex101.com/r/lB9jN7

Answer 4

$path = parse_url($url, PHP_URL_PATH);
$first = substr($path, 0, strpos($path, '/'));

检查这三个功能的文档。也许你不得不从路径的开头剥去斜线，我不确定。

Answer 5

你使用CodeIgniter ...... ???那么它可能是

$this->uri->segment(segment number of url);

需要在Controller中加载uri库