我正在尝试使用RegExp匹配此部分网址:
/l.php?u=http%3A%2F%2Fwww.transmoto.com.au%2Fpublish%2Fnews%2F14614708%2FBopping%2C-Styke-and-Waters-to-lead-Team-Australia-at-MXoN&h=5AQEDldxs&s=1
理想情况下,我需要匹配'u'值并将其转换为正确的url(即将%3A替换为:和%2F替换为/),但我很高兴只匹配整个表达式。
我尝试过多种RegExp组合,但没有取得任何成功。
答案 0 :(得分:0)
尝试:
var match = url.match(/u=([^&]+)/);
/* Alerts http%3A%2F%2Fwww.transmoto.com.au%2Fpublish%2Fnews%2F14614708
%2FBopping%2C-Styke-and-Waters-to-lead-Team-Australia-at-MXoN */
alert(match[1]);
/* Alerts http://www.transmoto.com.au/publish/news/14614708/Bopping,-Styke
-and-Waters-to-lead-Team-Australia-at-MXoN */
alert(decodeURIComponent(match[1]);
答案 1 :(得分:0)
var url = '/l.php?u=http%3A%2F%2Fwww.transmoto.com.au%2Fpublish%2Fnews%2F14614708%2FBopping%2C-Styke-and-Waters-to-lead-Team-Australia-at-MXoN&h=5AQEDldxs&s=1';
var re = url.match(/\?(?:|.*?&)u=([^&]+)/);
这是jsFiddle。