Question

我有一个“All_Data”表，其中包含“HR Manager”列，它包含“Employee Name”。我需要获取 NOT 的行来完成以下连接（意味着连接表中缺少的连接）。

HR_Manager:
Load [HR Manager] as [HR Full Name]
Resident All_Data;

inner Join(HR_Manager)
Load [Full Name] as [HR Full Name]
Resident All_Data;

有谁知道我怎么能在Qlikview中这样做？

THX，海伦

Answer 1

你用1分钟的时间击败我，弗朗西斯科，但你最后忘记了分号;）

HR_Manager:
Load [HR Manager] as [HR Full Name]
Resident All_Data;

inner Join(HR_Manager)
Load [Full Name] as [HR Full Name]
Resident All_Data;

AllTheOthers:

Load [Full Name] as [Employee Name]
resident All_Data
where not exists ([Full Name]);

如果这不是你想要的，那么以下可能会起作用

HR_Manager:
Load [HR Manager] as [HR Managers that are not employees]
Resident All_Data
Where not exists ([HR Manager],[Full Name]);

这将创建一个包含HR Manager字段中所有人员的表格，但不会出现在“姓名”字段中。

希望这有帮助，

詹姆斯。

Answer 2

我认为[全名]是＆＃34;员工姓名＆＃34;您在文中提到的字段。

这是你要表达的内容吗？：

New_Table:
Load [HR Manager] as [HR Full Name]
Resident All_Data
Where [HR Manager] <> [Full Name];

干杯，西蒙

Answer 3

HR_Manager:
Load [HR Manager] as [HR Full Name]
Resident All_Data;

inner Join(HR_Manager)
Load [Full Name] as [HR Full Name]
Resident All_Data;

AllTheOthers:

Load [Full Name] as [Employee Name]
resident All_Data
where not exists ([Full Name])

我怎么能在Qlikview中这样做？

3 个答案: