Question

共有4个表：

Suppl ，字段:( Code_name，Code_name_arch，Tasknum，Pki_num，Group_eng，Name，Descr，Cost，Quan，shop）;
制作者，字段：（Code_maker，Code_maker_arch，Code_name，provider）;
到达，字段：（Code_arr，Code_maker，quan_arr）;
帐户，字段：（Code_acc，Code_maker，num_acc，quan_acc，summ）

我的查询是：

ALTER Procedure [dbo].[pr_tblz] As
Set NOCOUNT ON
Declare @task VARCHAR(4000)
Select @task = coalesce(@task + ',[' + [Tasknum] + ']',
'[' + [Tasknum] + ']')
FROM [db_pki].[dbo].[Suppl]
Group BY [Tasknum]
Order BY [Tasknum]
Declare @query VARCHAR(8000)
Set @query='
Alter View Amountzz As
SELECT Shop, Name, Desc, Group_eng as GI, '+ @task +', quan_arr As specif, quan_acc As acns 
FROM 
(
select
Shop, Name, Desc, Group_eng, Tasknum, Quan, quan_arr, quan_acc
from [db_pki].[dbo].[Suppl] as deliveries
LEFT JOIN [db_pki].[dbo].[Maker] ON (deliveries.[Code_name] = [db_pki].[dbo].[Maker].[Code_name])
LEFT JOIN [db_pki].[dbo].[Arrival] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Arrival].[Code_maker])
LEFT JOIN [db_pki].[dbo].[Accounts] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Accounts].[Code_maker])
)date_to_pivot
PIVOT 
(
Max([Quan])
For [Tasknum]
IN (' + @task + ')
 )AS p'
Execute (@query)

结果：

Shop      Name     Descr    GI    n1     n2      n3 ...    specif    acns
1         name1      1       5    4                           1        1
2 10      name2      2       3    8                           2        2
3         name3      3       501         11                   3        3
1 8       name1      1       5           16                   7        10
a 2 10    name2      2       3                   3            5        6
5         name1      1       2                   5            6        3

如何获得以下结果？

Shop      Name     Descr    GI    n1     n2      n3 ...    specif    acns
1 8       name1      1       5    4      16                 8(1+7)     11
a 2 10    name2      2       3    8              3            7        8(2+6)
3         name3      3      501          11                   3        3
5         name1      1       2                   5            6        3

n1，n2，n3，... - Tasknum

Answer 1

未经过测试。尝试在旋转前拉取列的子选择中聚合Shop，specif和acns的值，如下所示（必要的更改以粗体突出显示：

ALTER Procedure [dbo].[pr_tblz] As
Set NOCOUNT ON
Declare @task VARCHAR(4000)
Select @task = coalesce(@task + ',[' + [Tasknum] + ']',
'[' + [Tasknum] + ']')
FROM [db_pki].[dbo].[Suppl]
Group BY [Tasknum]
Order BY [Tasknum]
Declare @query VARCHAR(8000)
Set @query='
Alter View Amountzz As
SELECT Shop, Name, Desc, Group_eng as GI, '+ @task +', quan_arr As specif, quan_acc As acns 
FROM 
(
select
MAX(Shop    ) OVER (PARTITION BY Name) AS Shop,
Name, Desc, Group_eng, Tasknum, Quan,
SUM(quan_arr) OVER (PARTITION BY Name) AS quan_arr,
SUM(quan_acc) OVER (PARTITION BY Name) AS quan_acc
from [db_pki].[dbo].[Suppl] as deliveries
LEFT JOIN [db_pki].[dbo].[Maker] ON (deliveries.[Code_name] = [db_pki].[dbo].[Maker].[Code_name])
LEFT JOIN [db_pki].[dbo].[Arrival] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Arrival].[Code_maker])
LEFT JOIN [db_pki].[dbo].[Accounts] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Accounts].[Code_maker])
)date_to_pivot
PIVOT 
(
Max([Quan])
For [Tasknum]
IN (' + @task + ')
 )AS p'
Execute (@query)

透视动态列

1 个答案: