Question

我的问题：我需要使用脚本以 HH：MI：SS 格式获取两个日期（时间）之间的差异。例如，如果我有两次：

2012/08/24 13:04:23
2012/08/24 14:15:32

我的结果将是：

1:11:09

要求：我是使用SAP的BusinessObjects Data Services Designer编写的，因此我的脚本必须满足其语法规则（点击here查看详细的pdf文档...如果你'不熟悉SAP的语法，只知道它真的有限......）。

我尝试了什么：目前我有一个函数（见下文），它将为用户提供一个他们可以在SQL函数中使用的SQL语句，它将为他们提供什么正在寻找，但我想让这个数据存储不可知。

这是我当前的功能（不是我真正想要的）：

#Use this with a SQL function. For example: SQL('DSS_USER', GetTimeDifferenceSQL($time_1, $time_2));

return '
with seconds as (
  select 24*60*60*(to_date(\'[$time_1]\', \'YYYY.MM.DD hh24:mi:ss\')
                    - to_date(\'[$time_2]\', \'YYYY.MM.DD hh24:mi:ss\')) seconds_diff 
  from dual
)
select to_char(trunc(sum(seconds_diff)/3600), \'FM999999990\')  || \':\' || to_char(trunc(mod(sum(seconds_diff),3600)/60), \'FM00\') || \':\' || to_char(mod(sum(seconds_diff),60), \'FM00\')
from seconds
';

这不起作用，因为我希望它独立于数据存储并且仅在脚本中计算。

我也尝试将日期转换为十进制数，然后在它们上使用JED_Time(int)函数，这是有效的，除了十进制是基数10和时间是基数无论什么......所以它不会工作。< / p>

我的举动：我很难说时间没有确定的基础......任何帮助都会非常棒！谢谢！

Answer 1

更简单的方法是使用数据类型Interval。

获取两个日期时间之间的秒数：

interval_to_char( $dtFrom - $dtTo , 'SS');

采用间隔并返回间隔的字符表示。

interval_to_char（[in] InputInterval As interval，[in] FormatString As varchar）as varchar

此功能也可用于获取分钟和小时。

Answer 2

这可能是也可能不完全准确，但我想我明白了。输入非常受欢迎。希望有一天这会帮助别人！

#Make sure that when we're finding the difference, we always take the lesser date from the greater date. We'll negate it at the end.
if ($time_1 < $time_2)
begin
  $temp_time = $time_1;
  $time_1 = $time_2;
  $time_2 = $temp_time;
end

#Get all value differences from the two times
$nanoseconds = to_decimal(to_char($time_1, 'FF'), '.', null, 0) - to_decimal(to_char($time_2, 'FF'), '.', null, 0);
$seconds = to_decimal(to_char($time_1, 'SS'), '.', null, 0) - to_decimal(to_char($time_2, 'SS'), '.', null, 0);
$minutes = to_decimal(to_char($time_1, 'MI'), '.', null, 0) - to_decimal(to_char($time_2, 'MI'), '.', null, 0);
$hours = to_decimal(to_char($time_1, 'HH24'), '.', null, 0) - to_decimal(to_char($time_2, 'HH24'), '.', null, 0);
$days = interval_to_char($time_1 - $time_2, 'D');

#fix nanoseconds
if ($nanoseconds >= 1000000000)
begin
  $seconds = $seconds + 1;
  $nanoseconds = $nanoseconds - 1000000000;
end

if ($nanoseconds < 0)
begin
  $seconds = $seconds -1;
  $nanoseconds = $nanoseconds + 1000000000;
end

#fix seconds
if ($seconds >= 60)
begin
  $minutes = $minutes + 1;
  $seconds = $seconds - 60;
end

if ($seconds < 0)
begin
  $minutes = $minutes -1;
  $seconds = $seconds + 60;
end

#fix minutes
if ($minutes >= 60)
begin
  $hours = $hours + 1;
  $minutes = $minutes - 60;
end

if ($minutes < 0)
begin
  $hours = $hours -1;
  $minutes = $minutes + 60;
end

#fix hours
if ($hours >= 24)
begin
  $days = $days + 1;
  $hours = $hours - 24;
end

if ($hours < 0)
begin
  $days = $days - 1;
  $hours = $hours + 24;
end

#fix days
if (trunc($days/365, 0) >= 1)
begin
  $years = trunc($days/365, 0);
  $days = $days - ($years * 365);
end

if (round($days/7, 0) > 0)
begin
  $weeks = round($days/7, 0);
  $days = $days - ($weeks * 7);
end

$ret = '';

if ($years > 0)
begin
  $ret = $years||' year'||ifthenelse($years = 1, '', 's')||' ';
end

if ($weeks > 0)
begin
  $ret = $ret||$weeks||' week'||ifthenelse($weeks = 1, '', 's')||' ';
end

if ($days > 0)
begin
  $ret = $ret||$days||' day'||ifthenelse($days = 1, '', 's')||' ';
end

$ret = $ret||$hours||':'||lpad($minutes, 2, '0')||':'||lpad($seconds, 2, '0')||':'||lpad(round($nanoseconds/1000000, 0), 3, '0');

#Negate it if the parameter values were swapped at the beginning (using $temp_time)
if ($temp_time is not null)
begin
  $ret = '-'||$ret;
end

return $ret;

HH：MI：SS两次之间的差异

2 个答案: