我对json / android解析有一点兴趣。
我正在使用json将数据从我的数据库解析为android textview。
但有些如何显示网址和标题。
有没有办法隐藏这个或修改代码,以便它没有显示?
http://www.wvvzondag2.nl/android/leesverslag.php {“introtext”:“我在数据库中的价值”}
我希望看到它从数据库中显示我的价值,所以没有网址和括号。
这是我正在使用的代码。
package wvv.zondag.app;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.text.Html;
import android.util.Log;
import android.widget.LinearLayout;
import android.widget.TextView;
public class Leesverslag extends Activity{
/** Called when the activity is first created. */
TextView txt;
public static final String KEY_121 = "http://www.wvvzondag2.nl/android/leesverslag.php";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.leesverslag);
LinearLayout mLinearlayout= (LinearLayout) findViewById(R.id.Linear);
txt = new TextView(this);
txt.setText("Connecting...");
mLinearlayout.addView(txt);
Runnable postRunnable = new Runnable() {
@Override
public void run() {
txt.setText(Html.fromHtml(getServerData(KEY_121)));
}
};
txt.post(postRunnable);
}
private String getServerData(String returnString) {
InputStream is = null;
String result = "";
//Value from last activity for database
String titelhoofd = getIntent().getStringExtra("titelverslag");
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("titel",titelhoofd));
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(KEY_121);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//parse json data
try{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
json_data.getString("introtext");
//Get an output to the screen
returnString += jArray.getJSONObject(i);
}
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
return returnString;
}
}
有人知道如何解决问题吗?
亲切的问候, 帕特里克
答案 0 :(得分:0)
创建变量
String strData = "";
然后使用
//parse json data
try{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
//Get an output to the screen
strData += json_data.getString("introtext");
}
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
return strData ;