我有两个表,TableA和TableB:
CREATE TABLE `TableA` (
`shared_id` int(10) unsigned NOT NULL default '0',
`foo` int(10) unsigned NOT NULL,
PRIMARY KEY (`shared_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1
CREATE TABLE `TableB` (
`shared_id` int(10) unsigned NOT NULL auto_increment,
`bar` int(10) unsigned NOT NULL,
KEY `shared_id` (`shared_id`)
) ENGINE=MyISAM AUTO_INCREMENT=1001 DEFAULT CHARSET=latin1
以下是我的问题:
SELECT TableB.bar
FROM TableB, TableA
WHERE TableA.foo = 1000
AND TableA.shared_id = TableB.shared_id;
问题在于:
mysql> explain SELECT TableB.bar FROM TableB, TableA WHERE TableA.foo = 1000 AND TableA.shared_id = TableB.shared_id;
+----+-------------+--------------+--------+---------------+---------+---------+------------------------------------------+------+-------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+--------------+--------+---------------+---------+---------+------------------------------------------+------+-------------+
| 1 | SIMPLE | TableB | ALL | shared_id | NULL | NULL | NULL | 1000 | |
| 1 | SIMPLE | TableA | eq_ref | PRIMARY | PRIMARY | 4 | MyDatabase.TableB.shared_id | 1 | Using where |
+----+-------------+--------------+--------+---------------+---------+---------+------------------------------------------+------+-------------+
是否有可以添加的索引会阻止TableB的全表扫描?
答案 0 :(得分:2)
Runcible,您的查询可能会使用一些重写。您应该始终在ON子句中而不是在WHERE中指定JOIN条件。
您的查询将变为:
SELECT TableB.bar
FROM TableB
JOIN TableA
ON TableB.shared_id = TableA.shared_id
AND TableA.foo = 1000;
您不仅想要这样做:
ALTER TABLE TableB ADD INDEX (shared_id,bar);
您需要按如下方式向A添加索引:
ALTER TABLE TableA ADD INDEX (foo, shared_id);
请执行此操作,并提供EXPLAIN输出。
另请注意,通过在(shared_id,bar)上添加索引,您只需使(shared_id)索引冗余。放弃它。