Question

我将char *转换为char **。每个单词必须折叠到数组。但只折叠第一个字。输入：“abc def 123” out（预期）：num == 3，arr == {“abc”，“def”，“123”} out（real）：num == 1，arr == {“abc”}

struct CommandArray
{
    vector<char*> Arr;
    USHORT Num;
};
CommandArray Text::StrToArray(LPSTR Str)
{
    CommandArray Out;
    LPSTR TempStr;
    Out.Num = 0;
    TempStr = strtok (Str," ");
    while(TempStr != NULL)
    {
        Out.Arr.push_back(TempStr);
        Out.Num++;
        TempStr = strtok(NULL," ");
    }
    return Out;
}

Answer 1

strtok修改了它的第一个参数（这就是为什么它是char*而不是char const*）。一个猜测是，在调用Text::StrToArray之后你也会这样做。

Answer 2

首先。使用cin.getline(input,32);获取以空格分隔的输入，cin>>input将无效。

关于char*到char**。下面的代码将每个单词折叠成一个数组。

#include<windows.h>
#include<vector>
#include<string>
#include<iostream>
using namespace std;


struct CommandArray
{
    vector<char*> Arr;
    USHORT Num;
};


CommandArray  StrToArray(LPSTR Str)
{
    CommandArray Out;
    LPSTR TempStr;
    Out.Num = 0;
    TempStr = strtok (Str," ");
    while(TempStr != NULL)
    {
        Out.Arr.push_back(TempStr);
        Out.Num++;
        TempStr = strtok(NULL," ");
    }
    return Out;
}


int main()
{

    int ROWS=80; //80 characters wide
    int COLUMNS=20;// 20 lines
    int i;

    char seperators[]   = " ,\t\n";
    char *token;    

    char* input_Dynamic1DCharPointerArray = new char[80];
    char **output_Dynamic2DCharPointerArray = 0;
    //memory allocated for elements of rows.
    output_Dynamic2DCharPointerArray = new char *[ROWS] ;
    //memory allocated for  elements of each column.
    for(   i = 0 ; i < ROWS ; i++ ) output_Dynamic2DCharPointerArray[i] = new char[COLUMNS];


    strcpy(input_Dynamic1DCharPointerArray,"apples 123 oranges 456 bananas 789 lemons 101112" );

    //cout<<"  \n";
    //cin.getline(input_Dynamic1DCharPointerArray,32);

    cout<<"  \ninput = "<<input_Dynamic1DCharPointerArray<<"  \n\n";
    cout<<"Output = \n";

   token = strtok( input_Dynamic1DCharPointerArray, seperators );  
   i=0;
   while( token != NULL )
   {
      strcpy(output_Dynamic2DCharPointerArray[i],token);

      cout<<output_Dynamic2DCharPointerArray[i]<<"  \n";

      token = strtok( NULL, seperators ); // C4996
      i++;
   }

    cout<<"  \n";
    delete[] input_Dynamic1DCharPointerArray;

    //free the allocated memory
    for(   i = 0 ; i < ROWS ; i++ )
    delete [] output_Dynamic2DCharPointerArray[i] ;
    delete [] output_Dynamic2DCharPointerArray ;

    return 0;
}

c ++不要工作周期

2 个答案: