Question

我是非常新的Android Soap Web服务我对使用Ksoap2在Android中使用soap web服务有一些了解，我编写了以下代码：使用ksoap2.jar我从WSDL文件中获取了名称空间和方法名称

package com.soapwebservices.pack;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;

public class SampleWSExampleActivity extends Activity {
    private static final String TAG = null;
    /** Called when the activity is first created. */
      final String NAMESPACE = "urn:sap-com:document:sap:soap:functions:mc-style";
         final String URL = "http://***************:8000/sap/bc/srt/wsdl/srvc_14DAE9C8D79F1EE196F1FC6C6518A345/wsdl11/allinone/ws_policy/document?sap-client=800&sap-user=********&sap-password=*******";
          final String METHOD_NAME = "Z_GET_CUST_GEN";
         final String SOAP_ACTION = "urn:sap-com:document:sap:soap:functions:mc-style/Z_GET_CUST_GEN";
      //    private static final String[] sampleACTV = new String[];
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);        
        SoapSerializationEnvelope envelope = 
            new SoapSerializationEnvelope(SoapEnvelope.VER11);

        envelope.setOutputSoapObject(request);
        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

        try {
            androidHttpTransport.call(SOAP_ACTION, envelope);
            SoapObject resultsRequestSOAP = (SoapObject) envelope.bodyIn;

            System.out.println("THE SOAP RESPONSE"+resultsRequestSOAP);

            //ACTV.setHint("Received :" + resultsRequestSOAP.toString());
        } catch (Exception e) {


            e.printStackTrace();
        }
    }
}  

when i run this program i got the following Exception but in some examples i got the success please see once and let me know where i am doing the mistake 


08-20 15:21:40.296: WARN/System.err(1668): org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <{http://schemas.xmlsoap.org/wsdl/}wsdl:definitions targetNamespace='urn:sap-com:document:sap:soap:functions:mc-style'>@1:686 in java.io.InputStreamReader@4052f658) 

How can handle that exc

Answer 1

你的代码可能没什么问题......

在意识到我没有将客户端指向我的服务后，我解决了我的XMLPullParser异常。它希望能够使用SOAP响应和请求，但是看到了wsdl。弄清楚这很棘手。我不确定你的System.err（1668）是什么，但我建议你这样做。

下载并附加android-ksoap2源代码，这样您就可以进入调用（F5），以便在调试ksoap2包中引发错误的位置时查看。

https://github.com/mosabua/ksoap2-android/downloads

和

Install and run the free SoapUI来测试web服务，并确切地找出正确的Action，方法，URL和命名空间，因为如果你的代码没问题，它们很可能是一个问题。这个介绍视频的前2分钟是我测试服务所需的全部内容。

最后用不同的语言编写一个简单的客户端 - 一旦我为web服务的项目添加了Web引用，我发现在VB.NET express中很容易做到。（这使我在SoapUI的帮助下使我的WS-I符合wsdl）

祝你好运找到解决方案。

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1 个答案: