假设我有一个以下文本文件，其中包含：
Non-Leaf Node: level=1 count=27 address=52
branch 0 : rect id 1
rect: -117.035332 -114.738449
32.269550 32.711048
branch 1 : rect id 2
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Leaf Node: level=0 count=23 address=1
Non-Leaf Node: level=1 count=31 address=53
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Leaf Node: level=0 count=21 address=42
Non-Leaf Node: level=1 count=31 address=81
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Leaf Node: level=0 count=26 address=24
Non-Leaf Node: level=1 count=31 address=113
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branch 1 : rect id 126
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Leaf Node: level=0 count=33 address=125
Non-Leaf Node: level=1 count=31 address=145
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Leaf Node: level=0 count=40 address=93
Non-Leaf Node: level=1 count=31 address=177
我想使用sed打印每行的每个坐标值。例如，它应该是：
-117.035332
-114.738449
32.269550
32.711048
如果考虑输入的第3行和第4行 请注意，“Non-Leaf”和“Node：”之间只有一个空格，“Node：”和“level = 1”之间有2个空格，“rect：”和坐标值之间的标签位于坐标值。如果它不可能由sed，那么请告诉我如何打印2个字符串之间的线条并将整个事件管理到与此相同的操作？
答案 0 :(得分：2)
您也可以使用awk。使用适当的记录分隔符，所需元素变得微不足道：
awk -v RS='rect:' 'NR > 1 { print $1, $2, $3, $4 }' infile
NR > 1跳过标题。
输出：
-117.035332 -114.738449 32.269550 32.711048
-117.037956 -114.758972 32.245251 32.684460
-117.010262 -114.773041 32.249630 32.674690
-117.054260 -114.791054 32.272289 32.668911
...
如果您希望输出与birei的答案相同，请分别设置OFS和ORS，分别为\n和\n\n：
awk -v RS='rect:' -v OFS='\n' -v ORS='\n\n' 'NR > 1 { print $1, $2, $3, $4 }' infile
输出：
-117.035332
-114.738449
32.269550
32.711048
-117.037956
-114.758972
32.245251
32.684460
-117.010262
-114.773041
32.249630
32.674690
-117.054260
-114.791054
32.272289
32.668911
...
答案 1 :(得分：1)
一种方式。避免使用-n开关自动打印，然后当一行与行首开始匹配时，删除它，追加以下行，删除多余空格，在坐标之间添加换行符并打印：
rect:假设sed -ne '/^rect:[\t]*/ { s/// ; N ; s/\n[ ]*/ / ; s/[ \t]\+/\n/g ; p }' infile
已在您的问题中粘贴了内容，则输出将为：
infile UPDATE 在坐标后添加字符串-117.035332
-114.738449
32.269550
32.711048
-117.037956
-114.758972
32.245251
32.684460
-117.010262
-114.773041
32.249630
32.674690
-117.054260
-114.791054
32.272289
32.668911
...
：
rect id命令：
sed输出：
sed -ne '
## In a line that matches "branch" at the beginning of the line:
## 1. Remove all characters until a colon and all spaces just after it.
## The result will be the "rect id" string.
## 2. Save it in the "hold space".
/^branch/ {
s/^[^:]*:[ \t]*//;
h
};
## In a line that matches "rect" at the beginning of the line:
## 1. Remove the content matched.
## 2. Append next line (it will be the second pair of coordinates).
## 3. Remove the newline character between coordinates.
## 4. Now all coordinates will be in the same line, so sustitute the
## spaces between coordinates with a newline character.
## 5. Print coordinates (one per line).
## 6. Get content of "hold space" (remember, the "rect id" saved before)
## and print it just after coordinaes.
/^rect:[\t]*/ {
s///;
N;
s/\n[ ]*/ /;
s/[ \t]\+/\n/g;
p;
g;
p
}
' infile
答案 2 :(得分：0)
sed -ne '/^rect:\t*/ { s///; N; s/\n\s*/ /; s/\s\+/\n/g; p }' inputfile