jQuery'clone'脚本与其他变量不起作用

时间:2012-08-20 09:38:21

标签: php jquery

我已经'克隆'了一个脚本,除了变量脚本与原始脚本完全相同!但它并没有完全奏效。它陷入了困境:

if(validConnection=="")
{
   $('#UsernameConnection').css('border-color','#00ff00');
   $('.ErrorUsernameConnection').text('');
   checkUsername1 = true;
}

其余代码在下面)

我一直在检查我是否在更改可变电源时犯了一些错误,但它们似乎都匹配得当。怎么了?如何使用不同的变量才能正常工作,而不是这次???

这是HTML:

<div id="Connection">   
<div class="Connection">
    Connection
    <a href="#" id="HideConnection"><strong>×</strong></a>  
</div>

<?php connection(); ?>

<div class="formConnection">
    <form method="POST" autocomplete="off" name="Connection">
        <label for="Connection">Username:</label><br/>
        <input type="text" name="UsernameConnection" id="UsernameConnection"/><br/>
        <span class="ErrorUsernameConnection"></span><br/>
        <label for="Connection">Password:</label><br/>
        <input type="password" name="PasswordConnection" id="PasswordConnection"/>
        <span class="ErrorPasswordConnection"></span><br/>
        <input type="checkbox" name="checkbox"/><label>Remember me</label><br/>
        <input type="submit" name="Connection" value="Log In" id="Connection" class="LogIn"/>       
    </form>
</div>

这是php:

    <?php
    if(isset($_POST['UsernameConnection']))
    {
        $Username1 = $_POST['UsernameConnection'];

        if(preg_match("/^([a-zA-Z0-9àáâãäåçèéêëìíîïðòóôõöùúûüýÿ]{1,}[._-\s]?)+[a-zA-Z0-9àáâãäåçèéêëìíîïðòóôõöùúûüýÿ]{1,}$/",$Username1))
        {
            echo "";
        }else
        {
            echo "Invalid";
        }
    }       
?>

和JS:

    $(document).ready(function(){

    var checkUsername1 = false;


    $('#UsernameConnection').keyup(function(){

        var Username1 = $('#UsernameConnection').val();

        if(Username1=="")
        {   
            $('#UsernameConnection').css('border-color','red');
            $('.ErrorUsernameConnection').text('Error message 1');
            checkUsername1 = "Username empty";
        }else
        {
            $.post('fonctions/validUsernameConnection.php',{Username1:Username1},function(validConnection)
            {
                $('.ErrorUsernameConnection').text(validConnection);

                if(validConnection=="")
                {
                    $('#UsernameConnection').css('border-color','#00ff00');
                    $('.ErrorUsernameConnection').text('');
                    checkUsername1 = true;
                }else
                {
                    $('#UsernameConnection').css('border-color','orange');
                    checkUsername1 = "Username Invalid";
                }
            });
        }
    });
});
PS:我对所有堆栈的网站都有点失落所以请原谅我,如果这不是正确的发布这个= /

1 个答案:

答案 0 :(得分:0)

问题似乎出在这一行

$.post('fonctions/validUsernameConnection.php',{Username1:Username1},
function(validConnection)

在你的PHP中你应该检查$ _POST ['Username1']而不是$ _POST ['UsernameConnection']