Question

我有一个我想要阅读的文件，它本身是在zip存档中压缩的。例如，parent.zip包含child.zip，其中包含child.txt。我在阅读child.zip时遇到了麻烦。任何人都可以更正我的代码吗？

我假设我需要将child.zip创建为类似文件的对象，然后使用第二个zipfile实例打开它，但是对于python我的zipfile.ZipFile（zfile.open（name））是傻的。它引发了一个zipfile.BadZip文件：“文件不是一个zip文件”（独立验证）child.zip

import zipfile
with zipfile.ZipFile("parent.zip", "r") as zfile:
    for name in zfile.namelist():
        if re.search(r'\.zip$', name) is not None:
            # We have a zip within a zip
            with **zipfile.ZipFile(zfile.open(name))** as zfile2:
                    for name2 in zfile2.namelist():
                        # Now we can extract
                        logging.info( "Found internal internal file: " + name2)
                        print "Processing code goes here"

Answer 1

当您在.open()实例上使用ZipFile调用时，确实会获得一个打开的文件句柄。但是，要读取一个zip文件，ZipFile类需要更多。它需要能够在该文件上搜索，并且.open()返回的对象在您的情况下是不可搜索的。只有Python 3（3.2及更高版本）生成一个支持搜索的ZipExFile对象（前提是外部zip文件的底层文件句柄是可搜索的，并且没有任何东西试图写入ZipFile对象）。 / p>

解决方法是使用.read()将整个zip条目读入内存，将其存储在BytesIO对象（可搜索的内存中文件）和Feed中那到ZipFile：

from io import BytesIO

# ...
        zfiledata = BytesIO(zfile.read(name))
        with zipfile.ZipFile(zfiledata) as zfile2:

或者，在您的示例中：

import zipfile
from io import BytesIO

with zipfile.ZipFile("parent.zip", "r") as zfile:
    for name in zfile.namelist():
        if re.search(r'\.zip$', name) is not None:
            # We have a zip within a zip
            zfiledata = BytesIO(zfile.read(name))
            with zipfile.ZipFile(zfiledata) as zfile2:
                for name2 in zfile2.namelist():
                    # Now we can extract
                    logging.info( "Found internal internal file: " + name2)
                    print "Processing code goes here"

Answer 2

要使用python33（在windows下但可能不相关），我必须这样做：

 import zipfile, re, io
    with zipfile.ZipFile(file, 'r') as zfile:
        for name in zfile.namelist():
            if re.search(r'\.zip$', name) != None:
                zfiledata = io.BytesIO(zfile.read(name))
                with zipfile.ZipFile(zfiledata) as zfile2:
                    for name2 in zfile2.namelist():
                        print(name2)

cStringIO不存在所以我使用了io.BytesIO

Answer 3

这是我提出的一项功能。（从here复制。）

def extract_nested_zipfile(path, parent_zip=None):
    """Returns a ZipFile specified by path, even if the path contains
    intermediary ZipFiles.  For example, /root/gparent.zip/parent.zip/child.zip
    will return a ZipFile that represents child.zip
    """

    def extract_inner_zipfile(parent_zip, child_zip_path):
        """Returns a ZipFile specified by child_zip_path that exists inside
        parent_zip.
        """
        memory_zip = StringIO()
        memory_zip.write(parent_zip.open(child_zip_path).read())
        return zipfile.ZipFile(memory_zip)

    if ('.zip' + os.sep) in path:
        (parent_zip_path, child_zip_path) = os.path.relpath(path).split(
            '.zip' + os.sep, 1)
        parent_zip_path += '.zip'

        if not parent_zip:
            # This is the top-level, so read from disk
            parent_zip = zipfile.ZipFile(parent_zip_path)
        else:
            # We're already in a zip, so pull it out and recurse
            parent_zip = extract_inner_zipfile(parent_zip, parent_zip_path)

        return extract_nested_zipfile(child_zip_path, parent_zip)
    else:
        if parent_zip:
            return extract_inner_zipfile(parent_zip, path)
        else:
            # If there is no nesting, it's easy!
            return zipfile.ZipFile(path)

这是我测试它的方式：

echo hello world > hi.txt
zip wrap1.zip hi.txt
zip wrap2.zip wrap1.zip
zip wrap3.zip wrap2.zip

print extract_nested_zipfile('/Users/mattfaus/dev/dev-git/wrap1.zip').open('hi.txt').read()
print extract_nested_zipfile('/Users/mattfaus/dev/dev-git/wrap2.zip/wrap1.zip').open('hi.txt').read()
print extract_nested_zipfile('/Users/mattfaus/dev/dev-git/wrap3.zip/wrap2.zip/wrap1.zip').open('hi.txt').read()

如何从Python中的zip文件中读取zip文件？

3 个答案: